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kifflom [539]
2 years ago
7

You have $5600. The best interest rate you can find is 3%

Mathematics
1 answer:
EleoNora [17]2 years ago
4 0

Answer:

18 years

Step-by-step explanation:

The formula for computing accrued amount A for a principal of P at an interest rate of r(in decimal) compounded n times in a year for t years is given by

A = P(1 + \frac{r}{n})^{nt}

Note that r is percentage converted to decimal. So 3% = 3/100 = 0.03

We can rearrange the above equation to:

\frac{A}{P} = (1 + \frac{r}{n})^{nt}

Taking logs on both sides

log(\frac{A}{P}) = log(1 + \frac{r}{n})^{nt}

This gives

log(\frac{A}{P}) =nt \times log(1 + \frac{r}{n})\\So,\\nt = \frac{log(\frac{A}{P})}{ log(1 + \frac{r}{n})}

In this particular problem, n = 4, , A= 9600, P = 5600, r =0.03, so r/n = 0.03/4 = 0.0075

1 + r/n = 1+0.0075 = 1.0075

4t = log(9600/5600)/log(1.0075) = log(1.714) / log(1.0075) = 0.234 /0.00325 = 72

t = 72/4 = 18 years

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The first numerator is 3 and the second is 17 not 2
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3 years ago
Given: circle k(O), m∠P=95°, m∠J=110°, m∠LK=125°<br> Find: m∠PJ
IRINA_888 [86]

Answer:

The measure of the arc PJ is 75\°

Step-by-step explanation:

step 1

Find the measure of angle L

we know that

In a inscribed quadrilateral opposite angles are supplementary

so

m

we have

m

substitute

m

m

step 2

Find the measure of arc KJ

we know that

The inscribed angle measures half that of the arc comprising

so

m

substitute the values

95\°=\frac{1}{2}(125\°+arc\ KJ)

190\°=(125\°+arc\ KJ)

arc\ KJ=190\°-125\°=65\°

step 3

Find the measure of arc PJ

we know that

The inscribed angle measures half that of the arc comprising

so

m

substitute the values

70\°=\frac{1}{2}(65\°+arc\ PJ)

140\°=(65\°+arc\ PJ)

arc\ PJ=140\°-65\°=75\°

5 0
3 years ago
What is 2017( as i year) minus 4000 years
balu736 [363]
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3 years ago
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What is the x-intercept for the equation? 3x + 6y = 24<br> -4<br> 4.<br> 8<br> -8
lesantik [10]

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8 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
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