Answer:
D. x = 10, m<TRS = 60°
Step-by-step explanation:
m<QRS = 122° (given)
m<QRT = (7x - 8)° (given)
m<TRS = (6x)° (given)
m<QRT + m<TRS = m<QRS (angle addition postulate)
(7x - 8)° + (6x)° = 122° (substitution)
Solve for x
7x - 8 + 6x = 122
Add like terms
13x - 8 = 122
13x = 122 + 8
13x = 130
x = 130/13
x = 10
✔️m<TRS = (6x)°
Plug in the value of x
m<TRS = (6*10)° = 60°
no it is more than 4x it is 6x
Since g(6)=6, and both functions are continuous, we have:
![\lim_{x \to 6} [3f(x)+f(x)g(x)] = 45\\\\\lim_{x \to 6} [3f(x)+6f(x)] = 45\\\\lim_{x \to 6} [9f(x)] = 45\\\\9\cdot lim_{x \to 6} f(x) = 45\\\\lim_{x \to 6} f(x)=5](https://tex.z-dn.net/?f=%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2Bf%28x%29g%28x%29%5D%20%3D%2045%5C%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B3f%28x%29%2B6f%28x%29%5D%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20%5B9f%28x%29%5D%20%3D%2045%5C%5C%5C%5C9%5Ccdot%20lim_%7Bx%20%5Cto%206%7D%20f%28x%29%20%3D%2045%5C%5C%5C%5Clim_%7Bx%20%5Cto%206%7D%20f%28x%29%3D5)
if a function is continuous at a point c, then

,
that is, in a c ∈ a continuous interval, f(c) and the limit of f as x approaches c are the same.
Thus, since

, f(6) = 5
Answer: 5
It will be a horizontal line at y=7 and shaded above. If you have pictures of the graph I can show which one it would be.