Y = -(1/2)(x-2)² +8
Re write it in standard form:
(y-8) = -1/2(x-2)² ↔ (y-k) = a(x-h)²
This parabola open downward (a = -1/2 <0), with a maximum shown in vertex
The vertex is (h , k) → Vertex(2 , 8)
focus(h, k +c )
a = 1/4c → -1/2 = 1/4c → c = -1/2, hence focus(2, 8-1/2) →focus(2,15/2)
Latus rectum: y-value = 15/2
Replace in the equation y with 15/2→→15/2 = -1/2(x-2)² + 8
Or -1/2(x-2)² +8 -15/2 = 0
Solving this quadratic equation gives x' = 3 and x" = 2, then
Latus rectum = 5
8 blocks because 2/10=1/5 so if they total 4/5 then 2/10+2/10+2/10+2/10=8/10=4/5
Answer:
H
Step-by-step explanation:
I have done the work before
F(x) = (2x-1)(x+2)/ (x+2)
f(x) = 2x-1
f(-2) = 2(-2)-1
f(-2) = -5
(1)
f(x) + g(x) = 3x + 2 + 2x + 5 = 5x + 7
f(x) - g(x) = 3x + 2 - 2x - 5 = x - 3
(2)
f(x) + g(x) = 4x - 1 + 3x - 4 = 7x - 5
f(x) - g(x) = 4x - 1 - 3x + 4 = x + 3
(3)
f(x) + g(x) = - 5x + 3 + 2x - 4 = - 3x - 1
f(x) - g(x) = - 5x + 3 - 2x + 4 = - 7x + 7
(4)
f(x) + g(x) = 3x - 4 - 2x + 3 = x - 1
f(x) - g(x) = 3x - 4 + 2x - 3 = 5x - 7
(5)
f(x) × g(x) = - 2(- x + 7 ) = 2x - 14
(6)
f(x) × g(x) = - 5(2x - 7) = - 10x + 35