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Liono4ka [1.6K]
2 years ago
10

Write the equation of the line in slope intercept form that has the given slope and the y-intercept

Mathematics
1 answer:
Ainat [17]2 years ago
6 0

4). y = 2x - 6

5). y = -1x + 3

6). y = -1/3x - 1

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Help me<br><br> g + 3 + 4(9 + 2) =
GrogVix [38]

Answer:

g+3 +36+8=

g+39+8=

g+47

You can't find an answer but this is how you would simplify it :)

Step-by-step explanation:

4 0
3 years ago
If (x+2) is a factor of x^3-6x^2+kx+10, k=
Alja [10]
If a binomial (x-a) is a factor of a polynomial, then a is a root of this polynomial.

(x+2)=(x-(-2)) \Rightarrow a=-2\\\\&#10;(-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\&#10;-8-24-2k+10=0\\&#10;-2k=22\\\&#10;\boxed{k=-11}&#10;

3 0
2 years ago
HOW TO PUT 12/15 IN SIMPLEST FORM
mr_godi [17]

Answer:

4/5

Step-by-step explanation:

we divide by 3 the numerator and the denominator:

(12/3) / (15/3)

we have:

4/5

5 0
3 years ago
Combine like terms to simplify the expression:<br><br> -7x + 3y - 2 + 6x - 1 - y2
diamong [38]
It seems that the expression is - 7x + 3y - 2 + 6x -1 - y^2

like terms:

-7x + 6x = - x

3y stands alone

-2 - 1 = -3

- y^2 stands alone

Answer: - x + 3y - 3 - y^2

[note: if the last term is not y^2 but 2y, then you have to combine +3y - 2y = y and the answer would be - x + y - 3]
5 0
3 years ago
Read 2 more answers
Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10
Alenkasestr [34]

Answer:  The correct option is (D) SET 4.

Step-by-step explanation:  We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

<em>Perpendicular² + Base² = Hypotenuse².</em>

<em>Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.</em>

SET 1 :  14 cm, 5 cm, 6 cm.  

We have

5^2+6^2=25+36=61,\\\\14^2=196.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 2 :  8 in., 12 in., 20 in.  

We have

8^2+12^2=64+144=208,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 3 :  10 mm, 20 mm, 30 mm.  

We have

10^2+20^2=100+400=500,\\\\30^2=900.

Therefore,

<em>Perpendicular² + Base² ≠ Hypotenuse².</em>

So, this set will not form a right-angled triangle.

SET 4 :  12 ft, 16 ft, 20 ft.  

We have

12^2+16^2=144+256=400,\\\\20^2=400.

Therefore,

<em>Perpendicular² + Base² = Hypotenuse².</em>

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0
3 years ago
Read 2 more answers
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