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3 years ago

12

Can you help me with this assignment

2 answers:

slamgirl [31]3 years ago

8 0

Where what assignment are you talking about

Marianna [84]3 years ago

7 0

Answer:

Where I don't see any assignment?

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Someone help me please! Thank u so much!!

jek_recluse [69]

5. a^2 + b^2 = c^2...where a and b are the legs and c is the hypotenuse
7^2 + 10^2 = c^2
49 + 100 =c^2
149 = c^2....take square root of both sides, eliminating the ^2
sq rt 149 = c
12.21 = c.....so the approximate length of 3rd side is 12 m

6. x = number of books bought

7. m < 2 + m < 8 = 180

8. 1000 = 400 + 24x
1000 - 400 = 24x
600 = 24x
600/24 = x
25 = x <=== 25 months he will have spent $ 1000

5 0

3 years ago

Factor the following binomials

Novay_Z [31]

We can’t see the picture it shows a black screen!!

4 0

3 years ago

Read 2 more answers

If you take four away four my number then divide the answer by three you will get 11

Svetlanka [38]

37. 37-4=33 33÷3=11 hope i helped

7 0

3 years ago

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

2 years ago

Please view the attachment.

quester [9]

-1 * (-4) = 4; 3 * (-4) = -12; 6 * (-4) = -24; -3 * (-4) = 12

7 0

3 years ago