m = mass of the roller coaster = 500 kg
h = height of the hill = 80 m
v = speed of the roller coaster at the bottom of the hill = ?
using conservation of energy
kinetic energy at the bottom of the hill = potential energy at the top of hill
(0.5) m v² = m g h
(0.5) v² = g h
inserting the values
(0.5) v² = (9.8) (80)
v = 39.6 m/s
hence the speed at the bottom comes out to be 39.6 m/s
Answer:
m₂ = 3kg
Explanation:
The question wasn't clear about what direction the initial velocity of the second cart was, so I'll assume it was going left at 2.0m/s.
Anyway, this is a conservation of momentum problem. The equation you need to use is the one written in blue. They want you to solve for the mass of the second cart, so do some algebra and rearrange that blue equation in term of m₂.
Now that you have the equation for m₂, plug in all the values given from the question and you'll get 3kg.
From the graph, the average acceleration between 5.0 s and 8.0 s is 2.33 ms^2.
<h3>What is acceleration?</h3>
The term acceleration has to do with the change in velocity with time. We can see that the graph shown is a graph of velocity against time, the slope of the graph is the acceleration.
Thus, the average acceleration between 5.0 s and 8.0 s can be read off from the graph as 20 m/s - 13m//8.0 s - 5.0 s = 2.33 ms^2.
Learn more about acceleration:brainly.com/question/12550364
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