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9966 [12]
3 years ago
6

You and your lab partner, Mel, are engrossed in a chemistry activity using beans to compute the average atomic mass of an elemen

t "beanium". You have three isotopes of beanium to measure. Using a triple beam balance, you find the mass of each isotope three times and then take an average. You and Mel compute an average mass for beanium of 8.93 grams and your percent error is 18%. Your teacher instructs you to try again and you end up with the same results. In fact, no matter how many times you try, your percent error is between 18 - 20%.
What is the MOST LIKELY source of error in this activity?

A) random error: Mel misreads the balance occassionally.
B) random error: You and Mel take turns reading the balance and do not read it to the same accuracy.
C) systematic error: The balance is not calibrated accurately, resulting in inaccurate measurements.
D) systematic error: Every now and then you or Mel stop to chat with your neighbors and lose track of what you are doing.
Physics
2 answers:
Vikentia [17]3 years ago
5 0

Answer:

C:

Explanation:

either C or A but A seems unlikely after multiple attempts. Although the question doesn't make it clear whether the balance is electric either way it could be wrong in someway and seems to be the most likely.

spin [16.1K]3 years ago
5 0

Answer:

The answer is C

Explanation:

I pretty sure it is correct

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PLEASE HELP!! ITS URGENT!!!​
Natasha2012 [34]

Answer:

F = 800 [N]

Explanation:

To be able to calculate this problem we must use the principle of momentum before and after the impact of the hammer.

We must summarize that after the impact the hammer does not move, therefore its speed is zero. In this way, we can propose the following equation.

ΣPbefore = ΣPafter

(m_{1}*v_{1}) - F*t = (m_{1}*v_{2})

where:

m₁ = mass of the hammer = 0.15 [m/s]

v₁ = velocity of the hammer = 8 [m/s]

F = force [N] (units of Newtons)

t = time = 0.0015 [s]

v₂ = velocity of the hammer after the impact = 0

(0.15*8)-(F*0.0015) = (0.15*0)\\F*0.0015 = 0.15*8\\F = 1.2/(0.0015)\\F = 800 [N]

Note: The force is taken as negative since it is exerted by the nail on the hammer and this force is directed in the opposite direction to the movement of the hammer.

6 0
3 years ago
What types of crust are colliding between the North American Plate and the Pacific Plate?
svet-max [94.6K]

Answer: G00gle got you bro

Explanation:

Yea

4 0
3 years ago
Calculate the east component of a resultant 32.5 m/s, 35.0° east of north.
ValentinkaMS [17]

Answer:

East component is: 18.64 m/s

Explanation:

If the resultant is 32.5 m/s directed 35 degrees east of north, then we use the sin(35) projection to find the east component of the velocity:

East component = 32.5 m/s * sin(35) = 18.64 m/s

4 0
3 years ago
Two loudspeakers are 1.60 m apart. A person stands 3.00 m from one speaker and 3.50 m from the other. (a) What is the lowest fre
VMariaS [17]

Answer:

Explanation:

Given

Distance between two loud speakers d=1.6\ m

Distance of person from one speaker x_1=3\ m

Distance of person from second speaker x_2=3.5\ m

Path difference between the waves is given by

x_2-x_1=(2m+1)\cdot \frac{\lambda }{2}

for destructive interference m=0 I.e.

x_2-x_1=\frac{\lambda }{2}

3.5-3=\frac{\lambda }{2}

\lambda =0.5\times 2

\lambda =1\ m

frequency is given by

f=\frac{v}{\lambda }

where v=velocity\ of\ sound\ (v=343\ m/s)

f=\frac{343}{1}=343\ Hz

For next frequency which will cause destructive interference is

i.e. m=1 and m=2

3.5-3=\frac{2\cdot 1+1}{2}\cdot \lambda

\lambda =\frac{1}{3}\ m

frequency corresponding to this is

f_2=\frac{343}{\frac{1}{3}}=1029\ Hz

for m=2

3.5-3=\frac{5}{2}\cdot \lambda

\lambda =\frac{1}{5}\ m

Frequency corresponding to this wavelength

f_3=\frac{343}{\frac{1}{5}}

f_3=1715\ Hz                        

8 0
4 years ago
__________ is the most common type of stretching.
Verizon [17]

Answer: static stretching

Explanation:

e.g rubberband

6 0
3 years ago
Read 2 more answers
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