a meteorite impact
Explanation:
What most likely cause the bowl - like structure is a meteorite impact.
This is can be deduced from the presence of iridium and bowl - like structure on the earth.
Iridium has a higher abundance in meteorite than the normal crustal abundance.
During a meteorite collision on the surface, it is often encounter in craters.
learn more:
Meteorite brainly.com/question/6536722
#learnwithBrainly
Answer:
It can be used in medicines.
_______________________
Here is some more info on how isotopes can be used.
https://www.britannica.com/science/radioactive-isotope
Answer:
The work-energy theorem states that a force acting on a particle as it moves over a <u>distance</u> changes the <u>kinetic</u> energy of the particle if the force has a component parallel to the motion.
Explanation:
The correct answer is presented below and all reasons are presented to explain all facts:
The work-energy theorem states that a force acting on a particle as it moves over a <u>distance</u> changes the <u>kinetic</u> energy of the particle if the force has a component parallel to the motion.
Reasons:
According to the Work-Energy Theorem, the work done on a particle () equals the change in its kinetic energy (). That is:
(1)
By definition of work we expand this definition:
(2)
Where:
- Vector force.
- Vector travelled distance.
And by definition of dot product we conclude that:
Where:
- Magnitude of the vector force.
- Magnitude of the differential of the vector travelled distance.
- Angle between vectors, measured in sexagesimal degrees.
- Initial and final position of the particle.
From this expression we infer that change in kinetic energy is maximum if and only if in every point of the path travelled by the particle. In addition, change in kinetic energy occurs when component of force parallel to path is not zero.
<span>Step 1 -- determine the acceleration of the 200-g block after bullet hits it
a = (coeff of friction) * g
g = acceleration due to gravity = 9.8 m/sec^2 (constant)
a = 0.400*9.8
a = 3.92 m/sec^2
Step 2 -- determine the speed of the block after the bullet hits it
Vf^2 - Vb^2 = 2(a)(s)
where
Vf = final velocity = 0 (since it will stop)
Vb = velocity of block after bullet hits it
a = -3.92 m/sec^2
s = stopping distance = 8 m (given)
Substituting values,
0 - Vb^2 = 2(-3.92)(8)
Vb^2 = 62.72
Vb = 7.92 m/sec.
M1V1 + M2V2 = (M1 + M2)Vb
where
M1 = mass of the bullet = 10 g (given) = 0.010 kg.
V1 = velocity of bullet before impact
M2 = mass of block = 200 g (given) = 0.2 kg.
V2 = initial velocity of block = 0
Vb = 7.92 m/sec
Substituting values,
0.010(V1) + 0.2(0) = (0.010 + 0.2)(7.92)
Solving for V1,
V1 = 166.32 m/sec.
Therefore the answer is (B) 166 m/s!</span>
The frequency of a wave with wavelength of 0.050 m and speed of 220 m/s is 4.4 kHz.
<u>Explanation:</u>
Frequency is the measure of repetition of a cycle in a given time. So it is inversely proportional to the wavelength and directly proportional to the speed.
As wavelength is the measure of distance covered by the wave and speed is the rate at which the distance is covered. Frequency will be the number of times a complete cycle will be repeated in that particular time.
Here the wave speed is given as 220 m/s and wavelength is given as 0.050 m.
Then
Thus, the frequency of a wave with wavelength of 0.050 m and speed of 220 m/s is 4.4 kHz.