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snow_tiger [21]
3 years ago
9

I didn't understand this to be honest I thought I had to find what jm and lm were together and then subtract from the whole tota

l...but ended up being wrong. whats the correct answer?​

Mathematics
1 answer:
prisoha [69]3 years ago
7 0

Answer:

The correct answer is 3x-2

Step-by-step explanation:

It gives you the expression for JM and LM, and it asks for JL. Therefore, if you take away LM from JM, you are left with JL. You must subtract 2x-6 from 5x-8.

∴5x-8-(2x-6)

Do not forget to distribute the negative since you are subtracting, so instead of subtracting 6 from 8, you will be adding 6 to 8 because two negatives make a positive.

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Sam has 1000 to distributed among two groups equally. Later ,the first part is divided among five children and second part is di
melisa1 [442]
So basically sam split the 1000 to 2 groups so we have 1000 ÷ 2
now the first group divided the 500 (since 1000÷ 2 is 500) among five children so it would be 500 ÷ 5 which equals 100 per child and the second group divided their 500 between to boys, so you would get 500÷2 which is 250
so for group one it would be: 1000÷2÷5 which equals 100 per child and the second group is 1000÷2÷2 which equals 250 for each brother
3 0
3 years ago
A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w
melamori03 [73]

Answer:

The hypothesis is:

<em>H₀</em>: p_{X}-p_{Y}=0.

<em>Hₐ</em>: p_{X}-p_{Y}.

Step-by-step explanation:

Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.

The information provided is:

n_{X}=150\\X=88\\n_{Y}=200\\Y=130

Compute the sample proportion of men and women who exercise regularly as follows:

\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587

\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and \hat p_{X}=0.587.

The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and \hat p_{Y}=0.65.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\hat p=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e. p_{X}-p_{Y}=0.

<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e. p_{X}-p_{Y}.

6 0
3 years ago
Read 2 more answers
There is 2 and 3/4 punds of roast beef and 1 and 7/8 pounds of turkey and 2 1/16 pounds of salami if you must put 1/4 of pound o
rosijanka [135]
<span>2 and 3/4 punds of roast beef   2  3/4 =  (4x2) + 3 /4=  11/4 roast beef

</span><span>1 and 7/8 pounds of turkey     1  7/8 =  15/8 </span>turkey 

2 1/16 pounds of salami     2 1/16      33/16 <span>salami

</span><span>if you  put 1/4 of pound of meat 
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15/8 turkey<span> divided  1/4 = 15/8   x 4 = 15/2  = 7 sandwishes
</span>
 33/16 salami divided <span> 1/4  = 33/16 x 4 = 33/ 4 = 8 sandwiches</span>
8 0
3 years ago
Plz do it all plz i will give brailest and thanks to best answer.
lawyer [7]
Hibsgdndgauebgisbeyj
3 0
3 years ago
Read 2 more answers
X + 5y = 28<br><br> 2x + 3y = 21
svp [43]

Answer: for first one  x=28-5y

second one x=-3/29(y-7)

Step-by-step explanation:

im sure its right

4 0
3 years ago
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