Range and y intercept are two characteristics they have in common
Answer:
The cross section will be an isosceles triangle
Step-by-step explanation:
The picture of the question in the attached figure N 1
we know that
If a plane passes through the axis of rotation of the cone, then the resultant cross-section will be a triangle with one vertex as the vertex of the cone and the two sides of the triangle through the vertex A will be equal.
Where the base of the triangle will be equal to the diameter of the circular base of cone and the two congruent sides of triangle will be equal to the slant height of the cone
therefore
The cross section will be an isosceles triangle
Answer:
The two numbers are -4 and -10.
Step-by-step explanation:
x+y=-14
x-y=6
----------
2x=-8
x=-8/2
x=-4
-4+y=-14
y=-14-(-4)=-14+4=-10
x=-4, y=-10.
Y = mx + b
slope(m) = 7
(5,30)...x = 5 and y = 30
now we sub and find b, the y int
30 = 7(5) + b
30 = 35 + b
30 - 35 = b
-5 = b
so ur equation is : y = 7x - 5 <==
<h3>
Answer: 161 degrees</h3>
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Explanation:
Line AE is a tangent while line AU is a secant. The angle formed by the secant and tangent lines connects with the arcs through this formula
secant tangent angle = (larger arc - smaller arc)/2
More specifically, we can say:
angle EAI = (arc EU - arc IE)/2
42 = ( (7m+5) - (3m-1) )/2
42*2 = (7m+5) - (3m-1)
84 = 7m+5 - 3m+1
84 = 4m+6
4m+6 = 84
4m = 84-6
4m = 78
m = 78/4
m = 39/2
m = 19.5
Use this value of m to compute each arc
- arc IE = 3m-1 = 3*19.5-1 = 57.5 degrees
- arc EU = 7m+5 = 7*19.5+5 = 141.5 degrees
Let's say arc IU is some unknown number x. It must add to the other two arc measures to form 360 degrees, which is a full circle.
(arc IU) + (arc IE) + (arc EU) = 360
x + 57.5 + 141.5 = 360
x + 199 = 360
x = 360-199
x = 161
The measure of minor arc IU is 161 degrees
