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blondinia [14]
2 years ago
10

A firm tested the durability of four different types of tires by having 4 Cadillacs each randomly equipped with one of the types

of tires. In similar fashion, 4 Fords were used, each randomly equipped with one of the tire types. In a like manner, 4 Volkswagens were each randomly outfitted with one of the four tire brands. Then each of the twelve cars ran over a test track until the tires showed signs of serious wear. At that point the average mileage of the three cars using one type of tire was compared to the average mileage of the three cars using the second type of tires, and so on. This design is:
Mathematics
1 answer:
storchak [24]2 years ago
6 0

Answer:

Randomized block design

Step-by-step explanation:

In the scenario described above, the subjects which are the different car types are grouped into fixed units of 4 called blocks with each unit then assigned randomly to a particular treatment condition, which are the 4 different types of tire. In the end, the mean mileage for each block is taken and compared to that of the other blocks. This type of research design improves the reliability of the result obtained as it also eliminates the occurrence of systematic error in the course of our experiment.

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You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you
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Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) =  -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

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