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svp [43]
3 years ago
6

NEED HELP QUICKLY! WILL OFFER BRAINIEST!!

Mathematics
2 answers:
Yakvenalex [24]3 years ago
5 0
The answer would be B because that’s what it says on the chart
liubo4ka [24]3 years ago
5 0
Sbsnsjkakalaidmdmsmakksksnbxc
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Approximate to pi 13.0909091
Korolek [52]
Pi= 3.14 So, multiply that by 3.14. Answer should be 41.105454574
6 0
4 years ago
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Jayden has 8 mints.his friend Michael has eight times as many mints as jayden.how many mints does michael have?
arsen [322]

64

(8)(8)=64

Eight times eight=sixty-four.

7 0
3 years ago
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A constant force of 85 N accelerates towards a 10 kg box from a speed of 3.0 m/s to a speed of 7.0 m/s as it goes 14 m along a h
photoshop1234 [79]

Answer:

Step-by-step explanation:

Let us find the acceleration of box .  

v² = u² + 2as

Putting the values

7² = 3² + 2 a x 14

a = 1.43 m /s²

If coefficient of friction be μ

force of friction = μ mg

= μ x 10 x 9.8

= 98μ

Net force pushing the box

= 85 - 98μ

Applying newton's second law

85 - 98μ = 10 x 1.43

98μ = 85 - 14.3

μ = .72

5 0
3 years ago
If a translation of T2, –7(x, y) is applied to ΔABC, what are the coordinates of B'?
NikAS [45]

The coordinates of B' are 3 and -12. so option D is correct (3, -12)

<h3>How to find the coordinates of B'?</h3>

The point P(x, y) may undergo translation to form P' by using a defined translation rule :

If given the rule T(a, b) synch that P undergoes translation on T; then we will have P'(x+a; y+b)

Therefore,

The point B has its coordinates as B(1, - 5)

Translation rule, T(2, - 7) then the coordination of B after undergoing transformation according to T2;

B(1, - 5) - - - > T(2, - 7) - - - - > B'(1+2 ; - 5+-7)

= B'(3, -12)

Hence, the coordinates of B' are 3 and -12. so option D is correct.

Learn more about the concept :

brainly.com/question/12463306

#SPJ1

8 0
2 years ago
10 POINTS!!<br> Find x. Assume that any segment that appears to be tangent is tangent.
Mice21 [21]

Answer:

10

Step-by-step explanation:

130+40+x =180

x=10

option 2 is correct

7 0
4 years ago
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