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3 years ago

Find an equation for the nth term of the arithmetic sequence. -20, -16, -12, -8, .

Mathematics

2 answers:

devlian [24]3 years ago

8 0

Answer:

1) a30=96

2) 30(-20+96)/2

3) 1140

ollegr [7]3 years ago

7 0

We are given with the sequence -20, -16, -12, -8. From this sequence, we can see that the arithmetic difference is +4, from -(-20 + 16). hence following the arithmetic formula of an = a1 + d *(n-1). Substituting, an = -20 + 4 *(n-1) where n is an integer

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15 × (-4) ÷ 5 please

Step2247 [10]

Answer: -12

Work: Since -4 is in parentheses, I did -4 / 5 first. After doing the division, I had gotten -0.8. I multiplied -0.8 by 15, and had gotten -12.

7 0

3 years ago

One plane can travel 30 miles per hour faster than another. one of them goes 185 miles in the same time it takes the other to go

ycow [4]

Plane #1 speed: x mph
Plane #2 speed: (x+30) mph

time = time becomes

170 mi 185 mi
---------- = --------------
x x+30

Solving for x, the speed of the slower plane, we get

170x + 5100 = 185 x
5100
Then 15x = 5100, and x = ---------- (mi/hr) = 340 mph
15

The slower plane flies at 340 mph, and the faster one at 370 mph.

6 0

3 years ago

Showing ALL calculations, whether this statement is valid

choli [55]

Answer:

RM79 608.51

Step-by-step explanation:

First year,

RM505 050.00×5%=RM505 050.00×5/100

=RM25 252.50

second year,

(RM505 050.00+RM25 252.50)×5%=RM530 302.50×5/100

=RM26 515.13

third year,

(RM530 302.50+RM26 515.13)×5%=RM556817.63×5/100

=RM27840.88

three years interest,

RM25 252.50+RM26 515.13+RM27840.88=RM79608.51

I don't know that is R or RM 

if it is R ,sorry

Hope can help!

8 0

3 years ago

What is the approximate area of a circular pond that has a radius of 35 meters?

Masteriza [31]

A=r^ 2 * pi=35^ 2 *3.14=3846.5m

7 0

3 years ago

PLEASE HELP! Limited time

Natali [406]

The answer is x=17. Since it says that the plot point is the answer to square root 4.1^2 = 16.81 which is closest to 17.

Hope this helps and hope you have a great day and brainiest is always appreciated

7 0

3 years ago