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3 years ago

True or False 2 is a root of x^6-9x^4+24x^2-16=0 two times

Mathematics

1 answer:

son4ous [18]3 years ago

8 0

Answer:

True

Step-by-step explanation:

No need for explanation

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What dose a and x equal <br> 2³x 5- (√-1) a+ 5a - 3÷ x³

ser-zykov [4K]

The terms in which value of x when substituted leaves final value of p(x) = "0".

Here, x - 2 is factor. So value of x is 2.

Substituting value of x we get,

p(x) = x3 - 3x + 5a

p(2) = 2*3 - 3(2) + 5a

0+ 8-6 + 5a

-2 = 5a

a= -0.4

Plz mark me as brainliest

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3 years ago

Cuanto es menos 7 mas 2

irina [24]

Answer:

the answer is -5. you could really just use a calculator this is pretty basic math.

Step-by-step explanation:

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3 years ago

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How do you express 45mins as percentange of 1hr30mins

Nonamiya [84]

45 minutes is half of an hour and 30 minutes

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3 years ago

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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

This equation has one solution.<br> 5(r–1) + 3r =7(r + 1)<br> What is the solution?

Nadusha1986 [10]

Answer:

R=12 is the solution

I don't know how to explain but it needs to be 20 characters

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3 years ago