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vitfil [10]
4 years ago
8

Make a table and graph: f(x)=x-2

Mathematics
1 answer:
Vaselesa [24]4 years ago
8 0
Graph using the slope and y-intercept.

Slope: 1
Y-intercept: -2
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3(m + 2) – 7 m = 18<br> PLEASE SHOW HOW YOU GOT THE ANSWER:)
Anton [14]
3(m + 2) - 7m = 18
= 3m + 6 - 7m = 18
= 3m - 7m = 18 - 6
= -4m = 12
= m = -12/4
m = -3

In short, Your Answer would be -3

Hope this helps!
6 0
3 years ago
The ride it strore rents bicycles.<br> The cost is 8.50
Mars2501 [29]

Answer:hello

Step-by-step explanation:

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HELP ASAP 10 POINTSSSS
dlinn [17]
Answer:
Y= -4 :)

Steps:
Apply rule
-y + 3 = 7
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-y + 3 - 3 = 7 - 3
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3 years ago
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What fraction, decimal and percentage of the diagram is shaded?
serg [7]

Answer:

where is the diagram????

8 0
3 years ago
Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturd
mestny [16]

Answer:

1) P(X = 8) = 0.1033

P(X = 9) = 0.0688

2) Expected number of 200 restaurants in which exactly 8 customers use the drive-through: 20.66

Expected number of 200 restaurants in which exactly 9 customers use the drive-through: 13.76

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Question 1. Use the Poisson distribution to calculate the probability that exactly 8 cars will use the drive-through between 12:00 midnight and 12:30 AM on a Saturday night at Wendy's. Do the same for exactly 9 cars.

Cars arrive at the Wendy's drive-through at a rate of 1 car every 5 minutes between the hours of 11:00 PM and 1:00 AM. on Saturday nights. This means that during 30 minutes, 6 cars expected to arrive. So \mu = 6.

P(X = 8)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 8) = \frac{e^{-6}*(6)^{8}}{(8)!} = 0.1033

P(X = 9)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 9) = \frac{e^{-6}*(6)^{9}}{(9)!} = 0.0688

Question 2. At how many of the 200 restaurants in the survey would you expect exactly 8 customers to use the drive-through? exactly 9 customers?

There is a 10.33 probability that 8 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.1033 = 20.66

There is a 6.88 probability that 9 customers would use the drive through for each restaurant.

So of 200, the expected number is

E(X) = 200*0.0688 = 13.76

8 0
3 years ago
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