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Usimov [2.4K]
3 years ago
7

What is 7 tenths spimplified

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
8 0
It is 0.7 I'm pretty sure but your not being very descriptive
omeli [17]3 years ago
4 0
It cant be simplified so it would be 3halfs and 5.7
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Sally went to the clearance rack at a department store and found a shirt she wanted to buy. The shirt was $36.00 and is on sale
jeka57 [31]

Answer:

33.34%.

Step-by-step explanation:

Given that,

The actual price of the shirt = $36

Price on sale = $24

We need to find the percent of the decrease. The formula for the percentage is given by :

\%=\dfrac{|\text{actual value-estimated value}|}{\text{actual value}}\times 100

Putting all the values,

\%=\dfrac{24-36}{36}\times 100\\\\=33.34\%

So, the percentage decrease in the price of the shirt is 33.34%.

6 0
3 years ago
What is two rays sharing a common endpoint?
Finger [1]
Two rays sharing a common endpoint is the vertex.

7 0
3 years ago
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Is the following relation a function? <br><br> A. Yes<br> B. No
worty [1.4K]
Yes............................
6 0
3 years ago
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In a normal distribution, 95% of the data fall within how many standard deviations of the mean? O A. Three standard deviations B
Galina-37 [17]

Answer:

Two standard deviations

Step-by-step explanation:

The Z score is obtained using the mean and standard deviation, according to the empirical. Rule, which gives percentage of values that lie within an interval estimate in a normal distribution ;

one standard deviation lie within 68% of the mean

Two standard deviations lie within 95%

Three standard deviations lie within 99.7%

Hence, for the question given, 95% fall within 2 standard deviations of the mean

4 0
2 years ago
A stadium has 45,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. If section C held 300 fewer
White raven [17]

Answer:

Let's define the variables:

A = number of seats in section A.

B = number of seats in section B.

C = number of seats in section C.

We have the equations:

A + B + C = 45,000.

C - 300 = B/2

A*$28 + B*$24 + C*$20 = $1,139,200

This is a system of equations, the first step to solve this is to isolate one variable in one of the equations, and then replace it in the others.

I will isolate C in the second equation:

C = B/2 + 300.

Now let's replace this in the other two equations:

A + B + B/2 + 300 = 45,000

A*$28 + B*$24 + (B/2 + 300)*$20 = $1,139,200

Let's simplify these equations:

A + B*(3/2) = 44,700

A*$28 + B*$34 + $6,000 = $1,139,200

Now let's isolate A in the first equation:

A = 44,700 - B*(3/2)

Let's replace this in the other equation:

(44,700 - B*(3/2))*$28 + B*$34 + $6,000 = $1,139,200

Now let's solve this for B.

-B*$8 + $1,252,200 = $1,139,200

-B*$8 =  $1,139,200 - $1,252,200  = -$113,000

B = $113,000/8 = 14,125

Now we can replace that in the equations:

A =  44,700 - B*(3/2) =  44,700 - 14,125*(3/2) = 23,512.5, that we should round up to 23,513.

And C = B/2 + 300 = 7362.5

As we rounded the previous one up, we should round this one down to 7362.

3 0
3 years ago
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