Answer:
f^-1(x) = ( x + 6 )/4
Step-by-step explanation:
f(x) is the same as...y = 4x + 6....and then try to make x the subject of formula
y + 6 = 4x
x = (y + 6)/4....then when writing f^-1(x)...replace y with x
f^-1(x) = ( x + 6 )/4
We have,
(2y)^3 × y^-1
Simplify the term (2y)^3
= 8y^3 × y^-1
Now, multiply the terms with the same base y by adding their exponents.
Note: Using exponent product rule x^y × x^z = x^(y+z)
= 8y^{3+(-1)}
= 8y^(3-1)
= 8y^(3-1)
= 8y^2
Their sum can be greater than two. There is nothing that states that they couldn't be. All it states it that the two factions sums are less than 1. I hoped this helps
Answer:
e = 16
Step-by-step explanation:
-5/6e - 2/3e = -24
-5/6e + -2/3e = -24
-3/2e = -24
e = 16
