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3 years ago

Whats the the midpoint between (2, -1) and (-6, 0).

Mathematics

2 answers:

nikitadnepr [17]3 years ago

4 0

Answer:

X Midpoint -2 Y Midpoint -0.5

goldenfox [79]3 years ago

4 0

Answer:

(-2, -.5)

Step-by-step explanation:

2-6=-4 -1+0=-1

-4/2=-2 -1/2=-.5

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Mario is constructing a square dart board. It will consist of a smaller square centered in a larger square. The smaller square m

Ivan

Answer:

6 inches.

Step-by-step explanation:

Let a represent side length of larger square.

We know that area of square is square of its side length, so area of the larger square will be $a^2$ .

The area of smaller square would be $4^2$ .

We will use proportions to solve our given problem.

$\frac{\text{Area of smaller square}}{\text{Area of larger square}}=\frac{4}{9}$

$\frac{4^2}{a^2}=\frac{4}{9}$

$\frac{16}{a^2}=\frac{4}{9}$

Cross multiply:

$4*a^2=16*9$

$\frac{4*a^2}{4}=\frac{16*9}{4}$

$a^2=36$

Take square root:

$a=\pm\sqrt{36}$

$a=\pm 6$

Since the length cannot be negative, therefore, the side length of larger square is 6 inches.

8 0

3 years ago

Please please help!!

shepuryov [24]

Answer:

$\large\boxed{x=0\ and\ x=\pi}$

Step-by-step explanation:

$\tan^2x\sec^2x+2\sec^2x-\tan^2x=2\\\\\text{Use}\ \tan x=\dfrac{\sin x}{\cos x},\ \sec x=\dfrac{1}{\cos x}:\\\\\left(\dfrac{\sin x}{\cos x}\right)^2\left(\dfrac{1}{\cos x}\right)^2+2\left(\dfrac{1}{\cos x}\right)^2-\left(\dfrac{\sin x}{\cos x}\right)^2=2\\\\\left(\dfrac{\sin^2x}{\cos^2x}\right)\left(\dfrac{1}{\cos^2x}\right)+\dfrac{2}{\cos^2x}-\dfrac{\sin^2x}{\cos^2x}=2$

$\dfrac{\sin^2x}{(\cos^2x)^2}+\dfrac{2-\sin^2x}{\cos^2x}=2\\\\\text{Use}\ \sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-(1-\cos^2x)}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{2-1+\cos^2x}{\cos^2x}=2\\\\\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{1+\cos^2x}{\cos^2x}=2$

$\dfrac{1-\cos^2x}{(\cos^2x)^2}+\dfrac{(1+\cos^2x)(\cos^2x)}{(\cos^2x)^2}=2\qquad\text{Use the distributive property}\\\\\dfrac{1-\cos^2x+\cos^2x+\cos^4x}{\cos^4x}=2\\\\\dfrac{1+\cos^4x}{\cos^4x}=2\qquad\text{multiply both sides by}\ \cos^4x\neq0\\\\1+\cos^4x=2\cos^4x\qquad\text{subtract}\ \cos^4x\ \text{from both sides}\\\\1=\cos^4x\iff \cos x=\pm\sqrt1\to\cos x=\pm1\\\\ x=k\pi\ for\ k\in\mathbb{Z}\\\\\text{On the interval}\ 0\leq x$

4 0

3 years ago

Determine the resulting polynomial: <br> f(x)=10x−5<br> g(x)=2x2+4x−4<br> Find: f(x)⋅g(x)

Lina20 [59]

40x^2 - 20x

(10x-5)(2*2+4x-4)
(10x-5)(4-4+4x)
(10x-5)(4x)
40x^2 - 20x

4 0

4 years ago

PREGUNTA 3PRODUCCION Y COSTOS DE UNA EMPRESA ………………. (04 PUNTOS)SEA q = f ( T / K ) .................... q = PRODUCTO TOTAL FISI

worty [1.4K]

Answer:

hi I am new here ☺ ✨ ☺ ✨ ☺ ✨ ☺

3 0

3 years ago

If red oak lumber weighs 63 pounds per cubic foot, how much does one cord of red oak weigh? (A cord is a measurement for bulk wo

dsp73

Answer: Option C. 8,064 pounds

Solution:

Unit weight: U=63 pounds/foot^3

Total Weight: W=?

W=U*V

Volume: V

Length: l=8 feet

Width: w=4 feet

Height: h=4 feet

V=l*w*h

Replacing the knwon values in the formula above:

V=(8 feet)*(4 feet)*(4 feet)

V=128 feet^3

Replacing in the formula of total Weight:

W=U*V

W=(63 pounds/foot^3)*(128 feet^3)

W=8,064 pounds

8 0

3 years ago