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Darina [25.2K]
3 years ago
7

PLEASE ONLY RIGHT ANSWERS BIG PART OF MY GRADE!! BRAINLIEST!!!!!!

Mathematics
2 answers:
Tresset [83]3 years ago
8 0

Answer:

138

Step-by-step explanation:

Substitute c for 5 and d for 4

6(5)^2 - 5(4) + 8

6 · 25 - 5 · 4 + 8

150 - 20 + 8

= <u>138</u>

lubasha [3.4K]3 years ago
4 0

Answer:

138

Step-by-step explanation:

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If a number is raised to a power of 2, it is A. CubbedB. Powered C. Squared
xeze [42]

If we raise a number to a power of 2, we can represent the result graphically as shown below (where n is the number to be raised to a power of 2)

This is a square of side equal to n.

Therefore, the answer is option C, squared.

6 0
1 year ago
H = vt - 16t^2, solve for v
Sophie [7]
H=vt-16t²
vt-16t²=H
vt=16t²+H
v=(16t²+H)/t
v=16(t²/t)+H/t
v=16t+H/t

Answer: the answer would be: v=16t+H/t
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4 years ago
Help please please please please please<br> 6th &amp; 7th
raketka [301]

First lets start with number six. The only way to solve this is if you determine what "a" and "b" are using the first log they have given to you. log_a_ba=\frac{1}{3}

The first variable that I solved for was "a" and a=e^\frac{in(b)}{2}[tex]{[tex]  0}

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is a=\frac{1}{2} , b=\frac{1}{4}

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}}  )= -\frac{1}{18} and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. x=2,-2,\sqrt{2}, and -\sqrt{2} . (This does not account for any complex solutions)

Notice that the bases are conjugates which is why the answers are so "nice"

The key is in the exponents

if x^{2} -3 =1 then the sum on the conjugates will be 10 so

x^{2}-3=1
x^{2}=4
so x= 2 or -2

Now for the other two

the solution is also true if x^{2}-3=-1

so

x^{2}-3 = -1\\x^{2}=2\\x=\left \{ {{\sqrt{2}} \atop {-\sqrt{2}}} \right.

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6 0
3 years ago
Factorize: (a+1) (a+2)​
eimsori [14]

Answer:

a^2+3a+2

Step-by-step explanation:

(a+1)(a+2)

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a^2+2a+a+2

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5 0
3 years ago
Please help!!!! Consider the region shaded in yellow. Which inequality does the shaded region correspond to?
denis-greek [22]

Answer:

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Step-by-step explanation:

according to the graph (0,1) and (-1,0) lies on the doted line,

equation of the dotted line is y-x-1=0

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5 0
2 years ago
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