Step-by-step explanation:
here's the answer to your question
Answer:




Solving for
we got
and replacing this we got:



And then the best option for this case would be:
b.csc x
Step-by-step explanation:
For this case we have the following expression given:

We know from math properties that the definition for cot is 
If we use this definition we got:


Now we can use the following identity:

Solving for
we got
and replacing this we got:



And then the best option for this case would be:
b.csc x
Answer:
Both Lindsay and Sharon are wrong.
Step-by-step explanation:
When Lindsay was doing her problem, she put 100 on the bottom and 45 on the top, when it should have been the other way around.
Sharon would have been correct if she had used the right measuring unit. 2/5 of a milliliter should have been 2/5 of a liter.
As you notice by the table, the “y” value, f(x), is decreased in g(x). Therefore, it undergoes vertical compression.