If f(x) = (2x² + 5), then f'(x)
1 answer:
<h3>
Answer: f ' (x) = 4x</h3>
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Work Shown:
f(x) = 2x^2 + 5
f ' (x) = d/dx[ 2x^2 + 5 ]
f ' (x) = d/dx[ 2x^2 ] + d/dx[ 5 ]
f ' (x) = 2*d/dx[ x^2 ] + d/dx[ 5 ]
f ' (x) = 2*2x^1 + 0
f ' (x) = 4x
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