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Alexus [3.1K]
3 years ago
9

I’m in Algebra 2 and we’re currently on the subject of “Solving Absolute Value Equations” and I’m having trouble with this equat

ion. Please help!

Mathematics
1 answer:
saw5 [17]3 years ago
6 0

let's bear in mind that an absolute value expression is in effect a piece-wise expression,  namely it has a ± versions of the same expression.

\bf 5|3x-4| = x+1\implies |3x-4|=\cfrac{x+1}{5}\implies \begin{cases} +(3x-4)=\cfrac{x+1}{5}\\[1em] -(3x-4)=\cfrac{x+1}{5} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ +(3x-4)=\cfrac{x+1}{5}\implies 3x-4=\cfrac{x+1}{5}\implies 15x-20=x+1 \\\\\\ 14x-20=1\implies 14x=21\implies x = \cfrac{21}{14}\implies \boxed{x=\cfrac{3}{2}} \\\\[-0.35em] ~\dotfill\\\\ -(3x-4)=\cfrac{x+1}{5}\implies -3x+4=\cfrac{x+1}{5}\implies -15x+20=x+1 \\\\\\ 20=16x+1\implies 19=16x\implies \boxed{\cfrac{19}{16}=x}

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<h3>What is geometric transformation?</h3>

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