Question

Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution according to the equation H C 2 H 3 O 2 + N a O H ⟶ H 2 O + N a C 2 H 3 O 2 If you require 32.98 mL of 0.1776 M N a O H solution to titrate 10.0 mL of H C 2 H 3 O 2 solution, what is the concentration of acetic acid in the vinegar?

Answer 1

The concentration of acetic acid in the vinegar is found to be 0.5857 M.

Explanation:

Here one mole of acetic acid is used to neutralize one mole of sodium hydroxide. According to the law of Volumetric analysis, we can write the equation as,

V1M1 = V2M2

V1 and M1 being the volume and molarity of NaOH

V2 and M2 being the volume and molarity of CH₃COOH

M2 = $\frac{V1M1}{V2}$

    = $\frac{32.98 \times 0.1776}{10}$

   = 0.5857 M

So the concentration of acetic acid in the vinegar is 0.5857 M.