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3 years ago

To DECREASE the % ionization of HNO2, which salt would you add to the solution A) NaCl B) KNO3 C) KNO3 D) NH4Cl E) NaOH

Chemistry

1 answer:

Rama09 [41]3 years ago

3 0

Explanation:

HNO₂ ionizes in the following way -

HNO₂ + H₂O ----> H₃O⁺ + NO₂⁻

Hence , if we add ions of NO₂⁻ , it will increase the concentration of these ions towards the right side , and the reaction will proceeds in the backward direction , because of the Le - Chateliers principle ,

Hence from the options given in the question , none will be able to bring the reaction , back , i.e. reduce the ionization .

But in case we use KNO₂ , then , it is capable to reduce the ionization of HNO₂ .

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In pure metals, the atoms are arranged in orderly _______ and _______

Ipatiy [6.2K]

Answer:

Rows and columns.

Explanation:

Each atom gives up some of its electrons to create a kind of sea of these randomly moving charged particles. It's these free-flowing electrons that make metals conductive.

4 0

3 years ago

If a 4L solution is 80% concentrated lime juice and 20% water, how much 30% concentrated lime juice must be added so that the co

miv72 [106K]

The volume of 30% concentrated lime juice that must be added to a 4L solution of 80% concentrated lime juice and 20% water is 6 L.

<h3>What are mixtures?</h3>

Mixtures are substances which are formed when two or more substances are physically combined together.

Mixtures are heterogenous in nature and the constituents can be easily separated.

The volume of 30% concentrated lime juice that must be added to a 4L solution of 80% concentrated lime juice and 20% water, so that the concentration of the resulting solution is 50% concentrated lime juice is determined as follows:

Let the volume of 30% lime juice required be x;

total volume of lime juice = 0.3x

For 80% lime juice, volume of lime juice = 0.8 * 4 = 3.2 L

New volume of lime juice = 4 + x

New amount of lime juice added = 3.2 + 0.3x

Also, new amount of lime juice = 0.5 * ( 4 + x)

3.2 + 0.3x = 0.5 * ( 4 + x)

0.2x = 1.2

x = 6 L

In conclusion, the volume to be added is obtained from the percent concentration.

Learn more about percent concentration at: brainly.com/question/19379932

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7 0

2 years ago

What do you understand by the corpuscular nature of chemistry

Tom [10]

Answer:

The corpuscular model of matter is a model of the microscopic structure of matter, which seeks to explain the properties and behavior in each state of aggregation

Explanation:

hope it helps you and give me a brainliest

8 0

2 years ago

When 80.0 mL of a 0.812 M barium chloride solution is combined with 40 mL of a 1.52 M potassium sulfate solution, 10.8 g of bari

BabaBlast [244]

Answer:

76.1%

Explanation:

The reaction that takes place is:

BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

First we determine how many moles of each reactant were added:

BaCl₂ ⇒ 80 mL * 0.812 M = 64.96 mmol BaCl₂

K₂SO₄ ⇒ 40 mL * 1.52 M = 60.8 mmol K₂SO₄

Thus K₂SO₄ is the limiting reactant.

Using the moles of the limiting reactant we calculate how many moles of BaSO₄ would have been produced if the % yield was 100%:

60.8 mmol K₂SO₄ * $\frac{1mmolBaSO_4}{1mmolK_2SO_4}$ = 60.8 mmol BaSO₄

Then we convert that theoretical amount into grams, using the molar mass of BaSO₄:

60.8 mmol BaSO₄ * 233.38 mg/mmol = 14189.504 mg BaSO₄

14189.504 mg BaSO₄ / 1000 = 14.2 g BaSO₄

Finally we calculate the % yield:

% yield = 10.8 g / 14.2 g * 100 %

% yield = 76.1%

7 0

3 years ago

A perfectly spherical balloon occupied 35°C of neon gas under a pressure of 2 atm.

lutik1710 [3]

Answer:

V₂ = 116126.75 cm³

Explanation:

Given data:

Radius of balloon = 15 cm

Initial pressure = 2 atm

Initial temperature = 35 °C (35 +273 = 308K)

Final temperature = -20°C (-20+273 = 253 K)

Final pressure = 0.3 atm

Final volume = ?

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

Initial volume of balloon:

V = 4/3πr³

V = 4/3×22/7×(15cm)³

V = 14137.17 cm³

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 2 atm × 14137.17 cm³ × 253 K / 308 K × 0.3 atm

V₂ = 7153408.02 atm .cm³. K / 61.6 K.atm

V₂ = 116126.75 cm³

3 0

3 years ago