Question

A student in the lab accidentally poured 45 mL of water into a graduated cylinder containing 15 mL of 3.0 M HCL. What is the concentration of the new solution?

Answer 1

Answer:

The correct approach is "1 M".

Explanation:

The given values are:

Volume of HCL,

V₁ = 45 ml

In prepared solution,

V₂ = 15 ml

Concentration,

C₁ = ?

C₂ = 3.0 M

As we know,

⇒  $V_1C_1=V_2C_2$

or,

⇒      $C_1=\frac{V_2C_2}{V_1}$

On substituting the values, we get

⇒           $=\frac{15\times 3}{45}$

⇒           $=\frac{45}{45}$

⇒           $=1 \ M$