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The lateral surface area of cone A is exactly 1/2 the lateral surface area of cylinder B. Cone A radius is r and height h - Cyli

Mrac [35]

The ratio of the lateral surface area of cone A to the lateral surface area of cylinder B is equal to $r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$ . (Correct choice: False)

<h3>What is the ratio of lateral area of cone to the lateral area of the cylinder?</h3>

In accordance with space geometry, the lateral areas of the cone and cylinder are described by the following equations:

Cone

$A_{l} = \pi \cdot r \cdot \sqrt{r^{2}+h^{2}}$ (1)

Cylinder

$A_{l} = 2\pi\cdot r\cdot h$ (2)

If we divide (2) by (1), then we have the following ratio:

$r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$

The ratio of the lateral surface area of cone A to the lateral surface area of cylinder B is equal to $r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}$ . (Correct choice: False)

To learn more on surface areas: brainly.com/question/2835293

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3 0

2 years ago

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elixir [45]

The answer is $50 per month

4 0

3 years ago

What is the most specific name for quadrilateral PQRS? parallelogram rectangle rhombus square

Anarel [89]

Answer:rhombus