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3 years ago

Solve (-4-7i)-(4+5i)-(2-i)

Mathematics

1 answer:

Mashcka [7]3 years ago

5 0

Answer: −10−11i

Simplify the expression

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Solve the absolute value equation and enter the solution in set notation.<br><br> |2x−3|−7=0

ziro4ka [17]

Answer:

The solutions are −5 and 1 .

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2 years ago

Math, pls answer now for points I wasted 20 points on this ASAP

allochka39001 [22]

Answer:

The answer to the problem is J

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2 years ago

Find the GCF of 8 and 12. WIll give brainliest for the best and most clear answer. :)

siniylev [52]

Answer:

GCF = 4

Step-by-step explanation:

The factors of 8 are: 1, 2, 4, 8

The factors of 12 are: 1, 2, 3, 4, 6, 12

The greatest common factor is 4.

I hope this helps :).

3 0

2 years ago

Read 2 more answers

When c=-7, evaluate 4(9/4+5/7c)

goblinko [34]

Hey there!

4(9/4 + 5/7c)

= 4(9/4 + 5/7(-7))

= 4(9/4) + 20/7(-7)

= 4(9/4) - 20

= 9 - 20

= -11

Therefore, your answer is: -11

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

7 0

2 years ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

2 years ago