yes sure, i learned this before so
1. a. make a proportion here, of percentage.
if you cross multiply and divide you get 90%.
1. b. obviously the empty seats would be 10%.
2. a. proportion again,
cross multiply then divide you ge 15%
3. 30% in decimal form is 0.3. multiply it then to the total amount, so 0.3 x 15 = 4.5
The questions is, when z=9, 3z = ? When you multiply 3*9, you get 27
Step 1
From the question;

We are required to find how many months it will take him to read 90 books
Step 2
We will use the ratio below to solve the problem.

Answer; It will take Bobby 9months to read 90 booj
Answer:
a) 18.4%
Step-by-step explanation:
Assuming a normal distribution, the z-score (z) for the probability of the average of the mosquitoes count being 'X' is given by:

Where 'μ' is the distribution mean, 'σ' is the standard deviation and 'n' is the number of square meters chosen.
For X = 81.8 and n=36:

A z-score of 0.9 is equivalent to the 81.59 th percentile in a normal distribution.
Therefore, the probability (P) that the average of those counts is more than 81.8 mosquitoes per square meter is:
