Answer:
Kindly check explanation
Step-by-step explanation:
A common problem with most research designs is bias, which could be introduced win several ways one if which is the favored selection of certain variables rather than being randomized. In the scenario above, the sampling time frame introduces a bias into the design as the tune span of pesticide use does not allay with that of the exposure history of the respondent. Therefore an entire lifetime evaluation of one variable and just 20 years evaluation of the other introduces a sampling bias into the research design. Similarly, evaluation the type of pesticide usage over certain time period may need to be considered as the effect of very old pesticides may differ from those used very recently.
Answer:
0.7325 to 5.6675 ug/dl
Step-by-step explanation:
The middle 90% will be 45% above the mean and 45% below the mean. This means
0.5-0.45 = 0.05 and
0.5+0.45 = 0.95
We use a z table. Look in the cells; find the values as close to 0.05 and 0.95 as we can get.
For 0.05, we have 0.0505 and 0.0495; since these are equidistant from 0.05, we use the value between them. 0.0505 is z=-1.64 and 0.0495 is z=1.65; this gives us z=-1.645.
For 0.95, we have 0.9495 and 0.9505; since these are equidistant from 0.95, we use the value between them. 0.9495 is z = 1.64 and 0.9505 is z=1.65; this gives us z = 1.645.
Now we use our z score formula,

Our two z scores are 1.645 and -1.645; our mean, μ, is 3.2; and our standard deviation, σ, is 1.5:

Multiply both sides by 1.5:

Add 3.2 to each side:
2.4675+3.2 = X-3.2+3.2
5.6675 = X

Multiply both sides by 1.5:

Add 3.2 to each side:
-2.4675+3.2 = X-3.2+3.2
0.7325 = X
Our range is from 0.7325 to 5.6675.
Answer:
The least possible sum for a+b+c is 18.
Step-by-step explanation:
As given a,b and c are positive integers and abc = 210
So, let us consider some situation in which the product abc = 20
- If a, b and c are 5, 6 and 7 then
abc = 210 & a+b+c = 18
- If a, b and c are 3, 7 and 10 then
abc = 210 & a+b+c = 20
- If a, b and c are 7, 15 and 2 then
abc = 24 & a+b+c = 24
- If a, b and c are 2, 5 and 21 then
abc = 210 & a+b+c = 28
From all of the above situation the least sum is 18 when a, b and c are 5, 6 and 7 respectively.
3/4=0.75 or 75%
1/2=0.5 or 50%
So, 3/4 is bigger.