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11Alexandr11 [23.1K]
3 years ago
14

A plane intersects a prism to form a cross section that is a polygon with five sides. The minimum number of sides that the polyg

on at the base of the prism must have is?
A.) 2
B.) 4
C.) 7
D.) 3
E.) 5
Mathematics
2 answers:
pychu [463]3 years ago
6 0
Since the plane if cutting through the prism to make 5 sides, than the original shape needs to have less than 5.
 A prism, is a 3D shape, so you can't have a 2 sided shape.

Now you have a choice of 3 or 4 sides.

A 3 sides shape is a triangle, which also can't be cut into a 5 sided prism,
 so the answer would need to be 4.
 The answer is B


Snowcat [4.5K]3 years ago
5 0

the answer is 4 for this question

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2 t-shirts and 3 hats costs £12.
Mariana [72]

Answer:

Cost of tshirt = £7.29

Cost of what = £0.86

Step-by-step explanation:

2t +3h = 12; 10t + 15h = 60

5t + 4h =33; 10t + 8h = 66

15h -8h = -6

7h = -6; h = -6/7; h = 0.86

2t +3(-6/7) =12

14t -18 = 84

14t = 102; t = 102/ 14; t=7.29

6 0
3 years ago
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andreyandreev [35.5K]

Answer:

The answer is "was the first time the Constitution defined what a citizen is"

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8 0
3 years ago
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Please help me with this math question​
scZoUnD [109]

Answer:

<h2>d : e : f = 4 : 3 : 6</h2>

Step-by-step explanation:

\bold{METHOD\ 1}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\to d=\dfrac{4}{3}e\\\\\text{Substitute it and}\ f=2e\ \text{to the ratio}\ d:e:f:\\\\\dfrac{4}{3}e:e:2e\qquad\text{cancel}\ e\\\\\dfrac{4}{3}:1:2\qquad\text{multiply by 3}\\\\\huge\boxed{4:3:6}

\bold{METHOD\ 2}\\\\6d=8e\qquad\text{divide both sides by 6}\\\\d=\dfrac{8}{6}e\qquad\text{divide both sides by}\ e\neq0\\\\\dfrac{d}{e}=\dfrac{4}{3}\to d:e=4:3\\\\2e=f\qquad\text{divide both sides by 2}\\\\e=\dfrac{f}{2}\to e=\dfrac{1}{2}f\qquad\text{divide both sides by}\ f\neq0\\\\\dfrac{e}{f}=\dfrac{1}{2}\to e:f=1:2\\\\\text{We have}\ d:e=4:3\ \text{and}\ e:f=1:2.

\text{We know}\ \dfrac{1}{2}=\dfrac{1\cdot3}{2\cdot3}=\dfrac{3}{6}\\\\\text{threfore}\ e:f=3:6\\\\\text{Now we have}\\\\\left\begin{array}{ccc}d:e=4:3\\e:f=3:6\end{array}\right\}\large{\boxed{d:e:f=4:3:6}}

6 0
3 years ago
A bag contains 8 purple marbles &amp; 12 green marbles. You choose one marble out of the bag without looking.
MrRissso [65]

Answer:

1. P(P) = 8/20 = 0.4

2. P(G) = 12/20 = 0.6

Step-by-step explanation:

Given;

Number of green marbles G = 12

Number of purple marbles P = 8

Total T = 12+8 = 20

The probability that you choose a purple marble P(P) is;

P(P) = number of purple marbles/total number of marbles

P(P) = P/T = 8/20 = 0.4

P(P) = 0.4

The probability that you choose a Green marble P(G) is;

P(G) = number of Green marbles/total number of marbles

P(G) = G/T = 12/20 = 0.6

P(G) = 0.6

6 0
3 years ago
Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide
Law Incorporation [45]
The probability that Jenny gets to choose lunch is  64%  0.64 (rounded) or 0.636.

Work:

Number of roses and carnations divided by the total number of flowers

<span>7/11 = 0.636 = 0.64 (rounded)

once again same answer
</span><span /><span>
</span>
4 0
3 years ago
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