Answer:
Clearly from 1 to 15 we can only have the sum 6,9,12 and 15 to be divisible by 3.
Now meaning we have 4! ( 4 factorial) which implies 4x3x2x1= 24 .
We have 24 ways to pick distinct integers that are divisible by 3.
Step-by-step explanation:
The first thing you need to do is to look for numbers that are divisible by 3. Then you take its factorial
Answer:
I think it's 44 aren't you adding?
5 is common factor
also x
reverse distributive
ab+ac=a(b+c)
5x(x)+5x(4)=5x(x+4)
last one
The answer to your question is 130.
