Set Events:
T=tests positive~T=tests negativeP=subject is pregnant~P=subject is not pregnant
We are givenP(T n ~P)=0.02P(~T n P)=0.03P(P)=0.7
recall by definition of conditional probabilityP(A|B)=P(A n B)/P(B)
Need to find P(P|~T)
First step: make a contingency diagram of probabilities (intersection, n)
P ~P sum
T 0.67 0.02 0.69=P(T)
~T 0.03 0.28 0.31=P(~T)
sum 0.70 0.30 1.00
=P(P) =P(~P)
therefore
P(P|~T)=P(P n ~T)/P(~T)=0.03/0.31 [ both read off the contingency table ]
=0.0968
Answer:
x = -4/3
Step-by-step explanation:
to solve for the value of x in the expression 2/3 (3x+2)=1x
we have
2(3x +2) /3 = x
6x + 4 /3 = x
using cross multiply technique
6x + 4 = 3 × x
6x + 4 = 3x
collect the like terms
6x -3x = -4
3x = -4
divide both sides by the coefficient of x
3x/3 = -4/3
x = -4/3
Answer:
b
Step-by-step explanation:
1 gallon=4 quarts=8 pints
1quart=2pints
2 gallons=4*2=8quarts=16pints
2 containers are 1 quart
8-2=6 quarts left
6quars=xpints
12pint=xpints
12 pint containers
