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kotegsom [21]
4 years ago
14

What is 160/3 in simplest form

Mathematics
2 answers:
lianna [129]4 years ago
6 0
Greetings!

You can't reduce 160/3 any further. However, you can convert it into a mixed number. 

Turn Into a Mixed Number:
160/3=53.333...
3*53=159
160-159=1

The Mixed Number would be:
53  \frac{1}{3}

Hope this helps.
-Benjamin
Pavel [41]4 years ago
5 0
No simple form but is 53.33333333 as a decimal.
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What is the means-to-MAD ratio of the two data sets, expressed as a decimal?
Nataliya [291]
Means-to-MAD ratio is something that wouldn't be hard to find out, but I've certainly <em />never even heard of it.

The mean (<span>µ) </span>of a set of data points is found by adding them up and dividing by the number of data points.

For our first set: \{1,\ 4.3,\ 1\}\rightarrow\frac{1+4.3+1}3=\frac{6.3}3=\boxed{2.1=\mu}

For our second set: \{2,\ 4.9,\ 1.2\}\rightarrow\frac{2+4.9+1.2}3=\frac{8.1}3=\boxed{2.7=\mu}

The mean absolute deviation is when you find the distance of each data point from the mean and then find the mean <em>of those distances.</em>

For our first set: \{1,\ 4.3\ 1\}\ has\ \mu=2.1.\\distances = \{1.1,\ 3.2,\ 1.1\}\rightarrow\frac{1.1+3.2+1.1}3=\frac{5.4}3=\boxed{1.8=MAD}
<em>
</em>For our second set: \{2,\ 4.9,\ 1.2\}\ has\ \mu=2.7\\distances=\{0.7,\ 2.2,\ 2.5\}\rightarrow\frac{0.7+2.2+2.5}3=\frac{5.4}3=\boxed{1.8=MAD}
<em>
</em>It wouldn't be hard to find the ratio between these for each set as the question asks...don't forget to put our ratio in simplest form!

For the first set: \frac{\mu}{MAD}=\frac{2.1}{1.8}=\frac{21}{18}=\boxed{\frac{7}6}
<em>
</em>For the second set: \frac{\mu}{MAD}=\frac{2.7}{1.8}=\frac{27}{18}=\frac{9}3=\boxed{\frac{3}1}
<em>(In a fraction, we would just put this as 3 because the ÷1 is redundant...however, because this is ratio, we have to keep it in)</em><em>


</em>
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