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kotegsom [21]
3 years ago
14

What is 160/3 in simplest form

Mathematics
2 answers:
lianna [129]3 years ago
6 0
Greetings!

You can't reduce 160/3 any further. However, you can convert it into a mixed number. 

Turn Into a Mixed Number:
160/3=53.333...
3*53=159
160-159=1

The Mixed Number would be:
53  \frac{1}{3}

Hope this helps.
-Benjamin
Pavel [41]3 years ago
5 0
No simple form but is 53.33333333 as a decimal.
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Answer:

EF

Step-by-step explanation:

A chord is a line segment whose endpoints both lie on the circle.

EF is the chord.

AC is the radius.

DC is a tangent.

FC is a secant.

The correct answer is the first choice.

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Answer:

Small box weighs 13.75 kg & large box weighs 15.75 kg

Step-by-step explanation:

We can write 2 simultaneous equation and solve for weight of each box.

<em>Let weight of large box be l and small box be s.</em>

<em />

"<u>3 large boxes and  5 small boxes has a total weight of  116 kilograms</u>":

3l+5s=116

and

"<u>9 large boxes and  7 small boxes has a total weight of  238 kilograms</u>":

9l+7s=238

<em>Now we can solve for l in the 1st equation and put it into 2nd equation and get s:</em>

<em>3l+5s=116\\3l=116-5s\\l=\frac{116-5s}{3}</em>

<em>now,</em>

<em>9l+7s=238\\9(\frac{116-5s}{3})+7s=238\\3(116-5s)+7s=238\\348-15s+7s=238\\348-238=15s-7s\\110=8s\\s=\frac{110}{8}=13.75</em>

<em />

<em>now we plug in 13.75 into s into equation of l to find s:</em>

<em>l=\frac{116-5s}{3}\\l=\frac{116-5(13.75)}{3}\\l=15.75</em>

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wlad13 [49]

Brad have 19 quarters and 27 nickels.

Step-by-step explanation:

Given,

Total worth of nickels and quarters = $6.10 = 6.10*100 = 610 cents

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Let,

x represent the number of quarters.

y represent the number of nickels.

According to given statement;

25x+5y=610     Eqn 1

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Putting value of y from Eqn 1 in Eqn 2

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Dividing both sides by 30

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Putting x=19 in Eqn 2

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Brad have 19 quarters and 27 nickels.

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/9369548
  • brainly.com/question/9328925

#LearnwithBrainly

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