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3 years ago

Find the x-intercept and y-interceppt of each graph

Mathematics

1 answer:

Paha777 [63]3 years ago

5 0

Answer:

11.) y-int:(0,1); x-int:(1,0)

12.) y-int:(0,8); x-int:(4,0)

13.) y-int:(0,-9); x-int:(-3,0)

14.) y-int:(0,-5); x-int:(-2.5,0)

Step-by-step explanation:

For each equation, first you have to graph it. Then to find the y-intercept, you mark and check where your line of your equation intersects the y-axis. To find the x-intercept, you mark and check where the line of your equation intersects the x-axis. The y-intercept always will have the coordinates of x=0 and the x-intercept always will have the coordinates of y=0.

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Please help me with these

Alex Ar [27]

When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
$\lim_{x \to 0} (\frac{sinx}{x}) = 1$
$\lim_{x \to 0} (\frac{tanx}{x}) = 1$
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) $\lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}$

We can do this using the first and second method.
Method 1: Direct evaluation:

Substitute x = 0 to the function.
$\frac{\sqrt{0} - 5}{0 - 25}$
$= \frac{-5}{-25}$
$= \frac{1}{5}$

Method 2: Rearranging the function

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

$\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}$
$= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}$
$= \frac{1}{5}$

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.

8 0

3 years ago

Point M is located in the third quadrant of the coordinate plane, as shown.

nevsk [136]

Answer:

It is in quadrant three

Step-by-step explanation:

The points of M means there x and y will both be negatives.

5 0

3 years ago

Read 2 more answers

Which relation does not represent a function? A) a vertical line B) y = 5 9 x - 3 C) a horizontal line D) {(1, 7), (3,7), (5, 7)

Alisiya [41]

Answer:

A) a vertical line does not represent a function.

Step-by-step explanation:

For a relation to be a function for each value of $x$ there must be only one value of $y$ . In other words a function is one in which each value in the domain set corresponds to only one value in the range set.

Let us check for this condition in the give choices:

A) a vertical line

A vertical line is given as $x=a$ which meas it is parallel to y-axis and has infinite number of $y$ values for a single $x$ value.

So, its Not a function

B) $y=\frac{5}{9}x-3$

For the given equation, on plugging in some $x$ value will give a single $y$ value.

So, its a Function

C) a horizontal line

A horizontal line is given as $y=a$ which meas it is parallel to x-axis and has infinite number of $x$ values giving a single $y$ value.

So, its a Function

D) {(1, 7), (3,7), (5, 7), (7,7)}

For the given set for different $x$ valuesthere is only one $y$ value.

So, its a Function

4 0

3 years ago

Read 2 more answers

How many 2 1/2 hour movie can be shown consecutively in a 20 hour period?

Cloud [144]

20/2.5 = 8
So 8 movies can be shown in 20 hours.

5 0

3 years ago

Read 2 more answers

The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho

lyudmila [28]

Answer:

The solution to f(x) = s(x) is x = 2012.

Explanation:

Rewrite the table and the choices for better understanding:

Enrollment at a Technical School

Year (x) First Year f(x) Second Year s(x)

2009 785 756

2010 740 785

2011 690 710

2012 732 732

2013 781 755

Which of the following statements is true based on the data in the table?

The solution to f(x) = s(x) is x = 2012.

The solution to f(x) = s(x) is x = 732.

The solution to f(x) = s(x) is x = 2011.

The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012, x = 2012.

Thus, the correct choice is the third one:

The solution to f(x) = s(x) is x = 2012.

5 0

4 years ago