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Gnoma [55]
3 years ago
7

PLEASE HELP

Mathematics
2 answers:
alexandr402 [8]3 years ago
6 0

Answer:B

Step-by-step explanation:

azamat3 years ago
5 0

Answer:

B. Transitive property

Step-by-step explanation:

Transitive property, just like in the case of transitive property of equality, which says that if m = n, and o = m, therefore, o = n.

This property is what is also applied in the given proof above.

Thus:

Since, <1 ≅ <5, and <3 ≅ <5, therefore,

<3 ≅ <5 by transitive property.

The answer is:

✅Transitive property

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If there is an outlier on the lower end of the graph the mean will go down. If there is an outlier at the higher end of the graph the mean will go up.
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What is 0.08 written as a percent
andrew11 [14]
0.08 can be written as 8%

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Please help 10 points each but beware if you use my points for no reason I'll report you
DochEvi [55]

Answer: 80 cubic centimeters

Step-by-step explanation:

Use the formula: V=\frac{1}{3}Bh

(B is the area of the pyramid's base)

V=\frac{1}{3}(16)(15)

Multiply: 16 x 15 =240

              \frac{1\\}{3} x 240 = 80

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4 0
2 years ago
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6
Drupady [299]

Answer:

  • (a) 1/2
  • (b) 1/3

Step-by-step explanation:

(a) 3 of the 6 numbers on the die are even, so the probability that one of them will show is 3/6 = 1/2.

__

(b) 2 of the 6 numbers on the die are less than 3, so the probability that one of them will show is 2/6 = 1/3.

5 0
3 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
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