<u>(-2)+2=0, (-0.5)+0.5=0, and (-5)+5=0</u>
All those equations answers are 0, please mark me brainiest, and hope I helped!
180 + 30x = 60 + 50x
⇒ 20x = 120
⇒ x = 6 minutes
<span>it will take 6 minutes for Millie to catch up with Ben</span>
Equation #1:
|2x - 3| = 17
The first solution is
2x - 3 = 17
2x = 17 + 3 = 20
x = 10
The second solution is
3 - 2x = 17
-2x = 17 - 3 = 14
x = -7
The solutions are x = 10 or x = -7.
Equation #2:
|5x + 3| = 12
The only solution is
5x + 3 = 12
5x = 12 - 3 = 9
x = 9/5
Let us examine the given answers.
a. Equation #1 and #2 have the same number of solutions.
FALSE
b. Equation @1 has more solutions than Equation #2.
TRUE
c. Equation #1 has fewer solutions than equation #2.
FALSE
d. None of the statements a,b, or c apply.
FALSE
Answer: b.
Answer:
Step-by-step explanation:
1) Initial water level = 30 feet
2) Rate of change = (30 - 25) / (0 - 1) = 5/(-1) = -5
5ft per hour
3) y-intercept = 30
Answer:
Step-by-step explanation:
Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.
Problem 1:
(x²)/4 +y²= 1
y= x+1
*substitute for y*
Now we have a one-variable equation we can solve-
x²/4 + (x+1)² = 1
x²/4 + (x+1)(x+1)= 1
x²/4 + x²+2x+1= 1
*subtract 1 from both sides to set equal to 0*
x²/4 +x^2+2x=0
x²/4 can also be 1/4 * x²
1/4 * x² +1*x² +2x = 0
*combine like terms*
5/4 * x^2+2x+ 0 =0
now, you can use the quadratic equation to solve for x
a= 5/4
b= 2
c=0
the syntax on this will be rough, but I'll do my best...
x= (-b ± √(b²-4ac))/(2a)
x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))
x= (-2 ±√(4-0))/(2.5)
x= (-2±2)/2.5
x will have 2 answers because of ±
x= 0 or x= 1.6
now plug that back into one of the equations and solve.
y= 0+1 = 1
y= 1.6+1= 2.6
Hopefully this explanation was enough to help you solve problem 2.
Problem 2:
x² + y² -16y +39= 0
y²- x² -9= 0
