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3 years ago

Please answer number 1

Mathematics

1 answer:

Kamila [148]3 years ago

6 0

All u have to do is subtract 175 from 250 which is... 75 Dollars he needs to raise Hope that helped Bye!

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He perimeter of the figure is given. Find the length of the indicated side.

77julia77 [94]

Answer:

who's he, is it me, cuz id call that a failed abortion

3 0

3 years ago

The area of the kite is 30 m2. What is the value of x? Explain

astra-53 [7]

Answer:

x = 5

Step-by-step explanation:

5 0

3 years ago

A parking lot is 20 feet long. One tortoise starts at the edge of the parking lot and moves at a rate of 6 feet per minute. Anot

anygoal [31]

Answer:

Kindly check explanation

Step-by-step explanation:

Length of parking lot = 20 feets

Speed of tortoise which starts at the edge = 6 feets per minute

Speed of tortoise which starts 4 feets from the edge = 2 feets per minute

Equation to represent when they will be in the same spot.

Distance = speed * time

Distance of Tortoise at edge = 6ft/min * t = 6t - - (1)

Distance of the other tortoise = (4 + 2t) - - - (2)

Equating both (1) and (2)

6t = 4 + 2t

6t - 2t = 4

4t = 4

t = 4/4

t = 1

Hence, they'll be at the same spot after 1 minute.

6 0

3 years ago

Write a + - x or ÷ sign in each box to make the equation true <br><br> 7 18 45 3 2 = 139

irina [24]

I mean, I don't know how to explain a generic way to solve this. Ask me about the specific train of thought if you are interested:

7 * 18 + 45 / 3 - 2 = 139

4 0

4 years ago

The average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 in

Murrr4er [49]

Answer:

Probability that average height would be shorter than 63 inches = 0.30854 .

Step-by-step explanation:

We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.

Also, a random sample of 4 women from this population is taken and their average height is computed.

Let X bar = Average height

The z score probability distribution for average height is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 64 inches

$\sigma$ = standard deviation = 4 inches

n = sample of women = 4

So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)

P(X bar < 63) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{63-64}{\frac{4}{\sqrt{4} } }$ ) = P(Z < -0.5) = 1 - P(Z <= 0.5)

= 1 - 0.69146 = 0.30854

Hence, it is 30.85% likely that average height would be shorter than 63 inches.

7 0

4 years ago