Answer:
1.7507
Step-by-step explanation:
See Image
Answer:
Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) =
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) =
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Answer:
D
Step-by-step explanation:
Brainliest?
ANSWER
EXPLANATION
The given binomial expansion is:
Compare this to
we have a=2x , b=-3y and n=10
We want to find the coefficient of the term
This implies that, r=5.
The terms in the expansion can be obtained using
We substitute the given values to obtain;
Hence the coefficient is;
Answer:
1. True
2. True
3. True
4. True
5. True
Step-by-step explanation:
I dont know of it is supposed to be true or not lol.