1. sean has 1 ⅛ sugar pies and 2 ²⁄₆ blueberry pies
2 answers:
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Between the probability of union and intersection, it's not clear what you're supposed to compute. (I would guess it's the probability of union.) But we do know that
For parts (a) and (b), you're given everything you need to determine
.
For part (c), if
and 
are mutually exclusive, then 
, so 
. If the given probability is 
, then you can find 
. But if this given probability is for the intersection, finding is impossible.
For part (d), if and are independent, then 
.
For parts (a) and (b), you're given everything you need to determine
For part (c), if
For part (d), if