Answer:
The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
Step-by-step explanation:
Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.
It is provided that
.
Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:


Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.
It looks like it’s Pythagorean theorem.
a^2 + b^2 =c^2
60^2+11^2=c^2
3,600+121=c^2
3,721=c^2
The square root of 3,721 is 61
So the answer should be 61
Bill's number is 235-7789. Josh's number is 987-7532. Hope this helps! Please give me brainliest!!
The answer would be 6 because you need to multiply the L by the H divided by to: 4x3+12 12/2 +6
Answer:
1.50
Step-by-step explanation: