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Nataly [62]
3 years ago
8

HALP HALP HALP HALP HALP

Mathematics
1 answer:
svp [43]3 years ago
7 0
The answer is a. because both sides line up
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4m+5+5m+40=180 Help!!!
OLEGan [10]

First, let's put all of the variables together.

4m + 5m + 5 + 40 = 180.

Add them.

M is the same multiplier, so we can add 4 and 5 together to make 9m.

Add 5 and 40.

9m + 45 = 180.

From here, we can go two ways. I will show the first way, which is my personal  preference.

We want to get rid of the coefficient on m to isolate it, so we must divide it by its coefficient. The coefficient on m is 9. So, divide m by 9. We must also divide everything else by 9.

9m/9 = 1m

45/9 = 5

180/9 = 20

Plug it in--

m + 5 = 20.

Subtract the 5 from both sides to isolate m.

m = 15.

4 0
3 years ago
Read 2 more answers
Is 3,728,292 divisible by 4?
Wittaler [7]

Answer:

Yes

Step-by-step explanation:

4 times 932073 equals 3728292

8 0
3 years ago
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I'm having problems solving linear equations with fractions<br>​
Firlakuza [10]
So first multiply the denominator by it self on both sides so say you have 2/3x=8 you would multiply it by 3 so then you have 2x=24 because the denominator cancels it’s self out and on the other side you multiply it by the denominator so 3•8=24. Once you have that you want to separate 2 from x so you would divide 2 on both sides making it x=12
4 0
4 years ago
Why is the lcm of two numbers never less than the larger number?
Lady bird [3.3K]
This involves a bit of logic in thinking about what LCM actually means.

LCM is the least common multiple. A common multiple is a multiple shared by two or more numbers. And by multiple, we mean some number multiplied by successive integers; this set contains multiples of 5 {5, 10, 15, 20, 25...}. You can see that the least (or lowest) common multiple is the lowest multiple shared by two numbers. Like for 6 and 9, you have {6, 12, 18, 24...} and {9, 18...}, so LCM(6,9) = 18. 

Now, if an LCM must be shared by both numbers, and to get a multiple of the largest number, you have to multiply by an integer greater than or equal to 1, then the LCM of two numbers can never be less than the larger of the twi numbers. Generally, if x and y are positive real numbers, and x is greater than y, LCM(x,y)  \leq x. 
4 0
4 years ago
Please help i been stuck on these type of problems for the last hr can sumone explain
slava [35]
False
False
False
True?
5 0
3 years ago
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