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photoshop1234 [79]
2 years ago
15

Help please asap................

Mathematics
1 answer:
iren2701 [21]2 years ago
7 0

Answer:

Linear pair

Step-by-step explanation:

<1 and <2 lie on a straight line.

Angles that lie on a straight line are considered as linear pair angles.

Linear pair angles sum up to 180°, which is the measure of a straight line angle.

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Choose the equivalent system of linear equations that will produce the same solution as the one given below.
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<span>C: 3x + 2y = 6
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3 years ago
What is the slope of the line passing through the points (-1,-7) and (-9, -2) ?​
Dominik [7]
The equation for slope is:
(y2 - y1) / (x2 - x1)

-2 -(-7) = 5
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Slope of the line:

5/-8 or -5/8
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a school held a tennis tournament. after each round one fourth of the players were eliminated. if there were 64 players at the s
Sveta_85 [38]

Answer:

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In STU, SU =18 and TU =13. Find m
erastova [34]

Answer:

m=22.2

Step-by-step explanation:

By using the Pythagorean’s theorem i.e

hypotenuse^2=opposite^2+adjacent^2

Where

Hypotenuse =unknown

Opposite =18

Adjacent =13

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3 0
3 years ago
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

8 0
3 years ago
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