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Nady [450]
3 years ago
8

If 3x + 7y = 12 and x-y= 1, then what is the value of 5x + 5y?

Mathematics
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

14.

Step-by-step explanation:

3x + 7y = 12

x - y = 1           Multiply this by -3:

-3x + 3y = -3     Add this to equation 1:

0 + 10y = 9

so y = 9/10 = 0.9.

x - 0.9 = 1

x = 1.9.

So 5x + 5y = 5*1.9 + 5*0.9

= 14.

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Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

5×2 = 10:

4×3^5 x^6 y^14 x^(5×2) y^10

5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

4×3×9^2 x^6 y^14 x^10 y^10

9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

4×243 x^16 y^24

4×243 = 972:

Answer: 972 x^16 y^24

8 0
2 years ago
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Masteriza [31]
To divide exponents they have to have the same base and then you just subtract the bottom exponent from the top exponent.

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k × 3^9-5 =
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8 0
2 years ago
The diagonals of a square are perpendicular bisectors of each other.<br> True or false ?
kirill [66]

Answer: True

Step-by-step explanation:

This is true because for a square, all angles and sides are equal. That is no side has a longer length than the other. The diagonals of a square are therefore perpendicular bisectors of each other.

I hope this is clear, please mark as brainliest answer

8 0
2 years ago
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Eddi Din [679]

Answer:

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Step-by-step explanation:

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3 years ago
Identify the statement as true or false.
Shalnov [3]
The answer to this question is false
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