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3 years ago

After Myong's cylindrical birthday cake was sliced, she received the slice at right. If her birthday cake originally

Mathematics

1 answer:

Talja [164]3 years ago

7 0

Answer:

97.53 in³

Step-by-step explanation:

The cylindrical birthday cake has a diameter (d) of 14 inches and a height (h) of 6 inches.

The radius of the cake (r) = diameter / 2 = 14 inches / 2 = 7 inches.

The volume of the full cake = πr²h = π(7²)6 = 924 in³

Since only a part of the cake was cut and given to Myong. The total measure of the cake is 360°, but the part given to her was 38°. Hence the volume of her slice is given as:

Volume of her slice = (38 / 360) * volume of the full cake = (38 / 360) * 924 = 97.53 in³

Volume of her slice = 97.53 in³

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PLEASE HELP ME! IS THIS CORRECT?

Amanda [17]

Answer:

yes

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The measure of the supplement of an angle is seven times as large as the measure of its complement find the measure of the angle

8090 [49]

Answer: original angle = 75°

Its supplement 105°

Its complement = 15°

Step-by-step explanation:

We know that,

Sum of supplementary angles is 180 degrees.
Sum of complementary angles is 90 degrees.

Let x be the original angle , then its supplement = 180° - x

its complement = 90° - x

As per given,

180° - x = 7(90° - x)

⇒ 180° - x = 630° - 7x

⇒ 7x- x = 630° -180°

⇒ 6 x = 450°

⇒ x = 75° [divide both sides by 6]

So, original angle = 75°

Its supplement = 180° - 75° = 105°

Its complement = 90° -75° = 15°

Hence, original angle = 75°

Its supplement 105°

Its complement = 15°

4 0

3 years ago

A swimming pool whose volume is 10 comma 000 gal contains water that is 0.03% chlorine. Starting at tequals0, city water conta

Katarina [22]

Answer:

C(60) = 2.7*10⁻⁴

t = 1870.72 s

Step-by-step explanation:

Let x(t) be the amount of chlorine in the pool at time t. Then the concentration of chlorine is

C(t) = 3*10⁻⁴*x(t).

The input rate is 6*(0.001/100) = 6*10⁻⁵.

The output rate is 6*C(t) = 6*(3*10⁻⁴*x(t)) = 18*10⁻⁴*x(t)

The initial condition is x(0) = C(0)*10⁴/3 = (0.03/100)*10⁴/3 = 1.

The problem is to find C(60) in percents and to find t such that 3*10⁻⁴*x(t) = 0.002/100.

Remember, 1 h = 60 minutes. The initial value problem is

dx/dt= 6*10⁻⁵ - 18*10⁻⁴x = - 6* 10⁻⁴*(3x - 10⁻¹) x(0) = 1.

The equation is separable. It can be rewritten as dx/(3x - 10⁻¹) = -6*10⁻⁴dt.

The integration of both sides gives us

Ln |3x - 0.1| / 3 = -6*10⁻⁴*t + C or |3x - 0.1| = e∧(3C)*e∧(-18*10⁻⁴t).

Therefore, 3x - 0.1 = C₁*e∧(-18*10⁻⁴t).

Plug in the initial condition t = 0, x = 1 to obtain C₁ = 2.9.

Thus the solution to the IVP is

x(t) = (1/3)(2.9*e∧(-18*10⁻⁴t)+0.1)

then

C(t) = 3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴t)+0.1)

If t = 60

We have

C(60) = 10⁻⁴*(2.9*e∧(-18*10⁻⁴*60)+0.1) = 2.7*10⁻⁴

Now, we obtain t such that 3*10⁻⁴*x(t) = 2*10⁻⁵

3*10⁻⁴*(1/3)(2.9*e∧(-18*10⁻⁴t)+0.1) = 2*10⁻⁵

t = 1870.72 s

7 0

3 years ago

The cash drawer of the market contains $227. There are six more $5 bills than $10 bills. The number of $1 bills is two more than

k0ka [10]

Answer:

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

Step-by-step explanation:

There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

$x + 5*y + 10*z = 227$

We know that there are six more 5 dollar bills than 10 dollar bills and that the number of 1 dollar bills is two more than 24 times the number of 10 dollar bills, therefore:

$y = z + 6\\x = 2 + 24*z$