All categories

3 years ago

The value of x is __ degrees, and the value of y is_degrees

Mathematics

2 answers:

solmaris [256]3 years ago

8 0

Answer:

x = 112°, y = 68°

Step-by-step explanation:

68° and y are corresponding angles and are congruent, then

y = 68°

x and y are adjacent angles and are corresponding ( sum to 180° ), then

x + y = 180°

x + 68° = 180° ( subtract 68° from both sides )

x = 112°

Rudiy273 years ago

7 0

Answer: x = 112, y = 68.

The way we can figure this out is by deciding which variable to find first. Since we know that lines p and q are parallel, we know that they intersect line m in the same manner. (They are kinda like the same line, just shifted along line m). Since the 68 degrees and y are at the same relative point on lines p and q along m, we know y = 68.

Now we can easily find x. Since a line is basically just a 180 degree angle no matter how you look at it, we know that 68 + x = 180, as these two angles together become a straight line. Thus, solve the equation and get x = 112 degrees.

You might be interested in

The volume of a cylinder is 4,000pi in.³ .The

miskamm [114]

Answer:

The answer to your question is r = 4 in

Step-by-step explanation:

Data

Volume = 4000 π in³

height = 250 in

radius = ?

Process

1.- Look the formula to calculate the volume of a cylinder

Volume = πr²h

2.- Solve for r²

r² = Volume / πh

3.- Substitution

r² = 4000π / π(250)

4.- Simplification

r² = 16

r = √16

5.- Result

r = 4 in

8 0

3 years ago

What is the area of parallelogram ABCD? ..

Hatshy [7]

Answer:

20 square units

Step-by-step explanation:

B * H

height = 5

base = 4

4 * 5

6 0

3 years ago

Let f(x) = 1/x^2 (a) Use the definition of the derivatve to find f'(x). (b) Find the equation of the tangent line at x=2

Verdich [7]

Answer:

(a) $f'(x)=-\frac{2}{x^3}$

(b) $y=-0.25x+0.75$

Step-by-step explanation:

The given function is

$f(x)=\frac{1}{x^2}$ .... (1)

According to the first principle of the derivative,

$f'(x)=lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{\frac{x^2-(x+h)^2}{x^2(x+h)^2}}{h}$

$f'(x)=lim_{h\rightarrow 0}\frac{x^2-x^2-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-2xh-h^2}{hx^2(x+h)^2}$

$f'(x)=lim_{h\rightarrow 0}\frac{-h(2x+h)}{hx^2(x+h)^2}$

Cancel out common factors.

$f'(x)=lim_{h\rightarrow 0}\frac{-(2x+h)}{x^2(x+h)^2}$

By applying limit, we get

$f'(x)=\frac{-(2x+0)}{x^2(x+0)^2}$

$f'(x)=\frac{-2x)}{x^4}$

$f'(x)=\frac{-2)}{x^3}$ .... (2)

Therefore $f'(x)=-\frac{2}{x^3}$ .

(b)

Put x=2, to find the y-coordinate of point of tangency.

$f(x)=\frac{1}{2^2}=\frac{1}{4}=0.25$

The coordinates of point of tangency are (2,0.25).

The slope of tangent at x=2 is

$m=(\frac{dy}{dx})_{x=2}=f'(x)_{x=2}$

Substitute x=2 in equation 2.

$f'(2)=\frac{-2}{(2)^3}=\frac{-2}{8}=\frac{-1}{4}=-0.25$

The slope of the tangent line at x=2 is -0.25.

The slope of tangent is -0.25 and the tangent passes through the point (2,0.25).

Using point slope form the equation of tangent is

$y-y_1=m(x-x_1)$

$y-0.25=-0.25(x-2)$

$y-0.25=-0.25x+0.5$

$y=-0.25x+0.5+0.25$

$y=-0.25x+0.75$

Therefore the equation of the tangent line at x=2 is y=-0.25x+0.75.

5 0

3 years ago

Solve the system using elimination. 2x-4y=-22 7x+5y=18 what are the coordinates

user100 [1]

Answer:

The coordinates are (22, 18)

Step-by-step explanation: hope this helps its a bit easy if ur in middle school

6 0

3 years ago

Maya starts with $300 in her bank account. Each month she spends $40. What is the slope in this equation , and what is the y- in

Neporo4naja [7]

Answer: y=300-40x

The y-intercept would be 300

The slope would be -40

Step-by-step explanation:

x=number of months

300 is the amount she starts with

Equation can also be written like so; y=-40x+300 just like in y=mx+b (slope intercept) form

6 0

3 years ago

The value of x is ____ degrees, and the value of y is___degrees

The value of x is __ degrees, and the value of y is_degrees