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valentinak56 [21]
3 years ago
7

Which of the following is an arithmetic sequence?

Mathematics
1 answer:
Travka [436]3 years ago
5 0

Step-by-step explanation:

C. n 1 2 3 4

an 3 6 9 15

hope this helps you

have a great day : )

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The square below has an area of 1+2x+x2 square meters. What expression represents the length of one side of the square?
vovikov84 [41]

Answer:

x+1

Step-by-step explanation:

A square = side* side

x²+2x+1 = (x+1)(x+1)

side = (x+1)

3 0
3 years ago
Monthly sales of a particular personal computer are expected to decline at the following rate of S'(t) computers per​ month, whe
Len [333]

Answer:

S(t) = -18t^\frac{5}{3}+2440

Company will take approximately 14 months

Step-by-step explanation:

Given function that shows the change rate of computers,

S'(t)=-30 t^{\frac{2}{3}}

Where,

t = number of months

On integrating,

\int S'(t) = -30\int t^{\frac{2}{3}} dt

S(t) = -30(\frac{t^{\frac{2}{3}+1}}{\frac{2}{3}+1})+C

S(t) = -30 (\frac{t^{\frac{2+3}{3}}}{\frac{2+3}{3}})+C

S(t) = -30(\frac{t^\frac{5}{3}}{\frac{5}{3}})+C

S(t) = -30(\frac{3t^\frac{5}{3}}{5})+C

S(t) =-18t^\frac{5}{3}+C

According to the question,

S(0) = 2,440,

\implies -18(0)^\frac{5}{3}+C=2440\implies C = 2440

Hence, the required function,

S(t) = -18t^\frac{5}{3}+2440

If S(t) = 1,000,

-18t^\frac{5}{3}+2440=1000

-18t^\frac{5}{3}=-1440

t^\frac{5}{3}=80

t = (80)^\frac{3}{5}\approx 13.86

6 0
3 years ago
A will can be written by ___ .
AleksandrR [38]
An financial planner
6 0
3 years ago
Read 2 more answers
F(x) = (x - 2)²(x+1)​
Inessa [10]

(x - 2)²(x+1)​

(x-2)(x-2)

multiply the two brackets together

(x)(x)=x^2

(x)(-2)=-2x

(-2)(x)=-2x

(-2)(-2)=4

x^2-2x-2x+4

x^2-4x+4

(x^2-4x+4)(x+1)

multiply the brackets together

(x^2)(x)=x^3

(x^2)(1)=x^2

(-4x)(x)=-4x^2

(-4x)(1)=-4x

(4)(1)=4

x^3+x^2-4x^2-4x+4x+4

Answer:

x^3-3x^2+4

5 0
3 years ago
Which values are solutions to the inequality below? <br><br>Check all that apply.<br><br>x2  25
lawyer [7]
B D and E
Hdhdhsmsndnsndnnsjsbdndndndhdjdndndhf
3 0
3 years ago
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