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Finger [1]
3 years ago
6

Reflect the given triangle over the y-axis. [3 6 3 ] [-3 3 3]

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0

Answer:

Step-by-step explanation:

\left[\begin{array}{ccc}x_{1} &x_{2} &x_{3} \\y_{1} &y_{2} &y_{3} \end{array}\right]  ---------> \left[\begin{array}{ccc}-x_{1} &-x_{2} &-x_{3} \\y_{1} &y_{2} &y_{3} \end{array}\right]

\left[\begin{array}{ccc}-3&-6&-3\\-3&3&3\end{array}\right]

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What is the slope of a line that is parallel to the line whose equation is 0.5x-5y=9
Tems11 [23]

0.5x - 5y = 9

<u>Make y the subject:</u>

5y = 0.5x - 9

y = 0.1x - 1.8

Match equation with y = mx + b

m = slope = 0.1

Parallel Slope = 0.1

Answer: The slope of the parallel line is 0.1

6 0
4 years ago
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Find the solution of the given system of equations
nignag [31]

Answer:

Point form-

(3,-2)

Equation Form:

x=3, y=-2

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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4 0
3 years ago
What is the magnitude of the resultant vector of z-y?
Kobotan [32]

For this case what we should do is take into account the following vectors:

z = (-1,5,3)\\y = (- 6.2, -1)

We must find the following subtraction of vectors:

z-y = (- 1,5,3) - (- 6,2, -1)

Subtracting component to component we have:

z-y = ((- 1 + 6), (5-2), (3 + 1))

By writing we have:

z-y = (5,3,4)

Then the module of the resulting vector is given by:

| z-y | = \sqrt {5 ^ 2 + 3 ^ 2 + 4 ^ 2}

Rewriting we have:

| z-y | = \sqrt {50}\\ | z-y | = \sqrt {2 * 25}\\ | z-y | = 5\sqrt {2}

Answer:

The module of the resulting vector is given by:

| z-y | = 5\sqrt {2}

option B

3 0
3 years ago
2/3 + x = 3 im doing this cuss its too short but thats the question
aliina [53]

This is an easy one.

first you move 2/3 to the other side

x=3-2/3

so you get

x=1/3

3 0
3 years ago
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Which equation describes the sum of the vectors plotted below?<br> -5
zalisa [80]

Answer:

Im not entirely sure but try B

6 0
4 years ago
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