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3241004551 [841]
2 years ago
13

Can anyone please help anyone bro

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
5 0
F(x) and g(x) were inverse functions, then if f(a) = b, then g(b) = a

f(x) = (5x+1) / x g(x) = x / (5x+1)

f(1) = 6, but g(6) = 6/31 ≠ 1

So, f(x) and g(x) are NOT inverse functions.
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The circumference of a circle is 18 pi inches what is the radius in inches of the circle
Ne4ueva [31]
The radius would be 9 using the formula C=2r
3 0
2 years ago
Cant solve this please help me <br><br> 9x-2y=8 <br> Y=2x+1
ki77a [65]
Substitute 2x+1 where y is in the equation:

9x-2(2x+1)=8

Then distribute the -2(2x+1)

9x-4x+2=8

Then combine like terms (the x)

5x+2=8

Then do -2 on both side of the equation sign

5x+2=8
- 2 -2

Then you'd get

5x=6

Then divide 5 on both sides

X= 1.2
5 0
2 years ago
Read 2 more answers
Suppose it is known that the distribution of purchase amounts by customers entering a popular retail store is approximately norm
iragen [17]

Answer:

a. 0.691

b. 0.382

c. 0.933

d. $88.490

e. $58.168

f. 5th percentile: $42.103

95th percentile: $107.897

Step-by-step explanation:

We have, for the purchase amounts by customers, a normal distribution with mean $75 and standard deviation of $20.

a. This can be calculated using the z-score:

z=\dfrac{X-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\P(X

The probability that a randomly selected customer spends less than $85 at this store is 0.691.

b. We have to calculate the z-scores for both values:

z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{65-75}{20}=\dfrac{-10}{20}=-0.5\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\\\P(65

The probability that a randomly selected customer spends between $65 and $85 at this store is 0.382.

c. We recalculate the z-score for X=45.

z=\dfrac{X-\mu}{\sigma}=\dfrac{45-75}{20}=\dfrac{-30}{20}=-1.5\\\\\\P(X>45)=P(z>-1.5)=0.933

The probability that a randomly selected customer spends more than $45 at this store is 0.933.

d. In this case, first we have to calculate the z-score that satisfies P(z<z*)=0.75, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

P(z

Then, we can calculate X as:

X^*=\mu+z^*\cdot\sigma=75+0.67449\cdot 20=75+13.4898=88.490

75% of the customers will not spend more than $88.49.

e. In this case, first we have to calculate the z-score that satisfies P(z>z*)=0.8, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

P(z>-0.84162)=0.80

Then, we can calculate X as:

X^*=\mu+z^*\cdot\sigma=75+(-0.84162)\cdot 20=75-16.8324=58.168

80% of the customers will spend more than $58.17.

f. We have to calculate the two points that are equidistant from the mean such that 90% of all customer purchases are between these values.

In terms of the z-score, we can express this as:

P(|z|

The value for z* is ±1.64485.

We can now calculate the values for X as:

X_1=\mu+z_1\cdot\sigma=75+(-1.64485)\cdot 20=75-32.897=42.103\\\\\\X_2=\mu+z_2\cdot\sigma=75+1.64485\cdot 20=75+32.897=107.897

5th percentile: $42.103

95th percentile: $107.897

5 0
3 years ago
2x³+4x²-2x³+x-32<br><br>A)1 B)2 C)3 D)0​
Gnoma [55]

Answer:

The degree is 2

Step-by-step explanation:

2x³ and -2x³ cancel each other out, so the expression would be 4x²+x-32.

The largest exponent value is 2, as shown in "4x²"

8 0
3 years ago
Read 2 more answers
A teacher gave a benchmark test to see how well her students were prepared for an
WARRIOR [948]

Answer:

rcfnjcndcndc

Step-by-step explanation:

d

6 0
2 years ago
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