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xxMikexx [17]
2 years ago
11

Which graph shows a proportional relationship with a unit rate of -2? no links please :(

Mathematics
2 answers:
exis [7]2 years ago
4 0

Answer:

not totally sure but I think its C

Nookie1986 [14]2 years ago
3 0

Answer:

A.

Step-by-step explanation:

Simply put, the line intersects on -2, -4, -6 and 2, 4, 6. So basically, the coordinates match up on each side of the origin.

I rlly hope I helped, good luck :)

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Janet’s savings account has $12.10 more than the $242 it had at the beginning of the year. What percent more was in the savings
Ilia_Sergeevich [38]
5% is the answer!! :)
5 0
3 years ago
There are four more girls than boys in Ms. Raub's class of 28 students. What is the ratio of number of girls to the number of bo
FinnZ [79.3K]
So there are x girls and x-4 boys and together they make 28:

x+x-4=28
2x-4=28
2x=32
x=16

so there are 16 girls and 12 boys.

the ratio is then 16:12, or we can simplify (by dividing both sides by 4): 4:3

so the best answer is 4:3.
4 0
3 years ago
I'm begging you! HELP ME
love history [14]
Okay first off. You want to combine like terms. 

2.75-1.5=1.25j 
2.25+3=5.25

Now you just fit those two answers into the final answer and you have:

1.25j+5.25.
7 0
3 years ago
Find the midpoint of AB if a (-1,7) and B (11,-1)​
Nady [450]

Answer:

  • (5, 3)

Step-by-step explanation:

<h3>Given </h3>
  • Points A(-1,7) and B (11,-1)​
<h3>To find</h3>
  • Midpoint of AB
<h3>Solution</h3>

<u>Using midpoint formula</u>

  • x = (-1 + 11)/2 = 10/2 = 5
  • y = (7 -1)/2 = 6/2 = 3

Midpoint is (5, 3)

8 0
3 years ago
Read 2 more answers
Write and equation for the shift of the parent graph y=1/x
SashulF [63]
You can think of this equation as \bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}

and thus apply the transformations to it as such

\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;% left side templates&#10;\begin{array}{llll}&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

1)  D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7
7 0
2 years ago
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