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2 years ago

Which graph shows a proportional relationship with a unit rate of -2? no links please :(

Mathematics

2 answers:

exis [7]2 years ago

4 0

Answer:

not totally sure but I think its C

Nookie1986 [14]2 years ago

3 0

Answer:

Step-by-step explanation:

Simply put, the line intersects on -2, -4, -6 and 2, 4, 6. So basically, the coordinates match up on each side of the origin.

I rlly hope I helped, good luck :)

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Janet’s savings account has $12.10 more than the $242 it had at the beginning of the year. What percent more was in the savings

Ilia_Sergeevich [38]

5% is the answer!! :)

5 0

3 years ago

There are four more girls than boys in Ms. Raub's class of 28 students. What is the ratio of number of girls to the number of bo

FinnZ [79.3K]

So there are x girls and x-4 boys and together they make 28:

x+x-4=28
2x-4=28
2x=32
x=16

so there are 16 girls and 12 boys.

the ratio is then 16:12, or we can simplify (by dividing both sides by 4): 4:3

so the best answer is 4:3.

4 0

3 years ago

I'm begging you! HELP ME

love history [14]

Okay first off. You want to combine like terms.

2.75-1.5=1.25j
2.25+3=5.25

Now you just fit those two answers into the final answer and you have:

1.25j+5.25.

7 0

3 years ago

Find the midpoint of AB if a (-1,7) and B (11,-1)

Nady [450]

Answer:

(5, 3)

Step-by-step explanation:

<h3>Given </h3>

Points A(-1,7) and B (11,-1)

Midpoint of AB

<h3>Solution</h3>

<u>Using midpoint formula</u>

x = (-1 + 11)/2 = 10/2 = 5
y = (7 -1)/2 = 6/2 = 3

Midpoint is (5, 3)

8 0

3 years ago

Read 2 more answers

Write and equation for the shift of the parent graph y=1/x

SashulF [63]

You can think of this equation as $\bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}$

and thus apply the transformations to it as such

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

1) D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7

7 0

2 years ago