All categories

3 years ago

>

Mathematics

2 answers:

Oksanka [162]3 years ago

6 0

Answer:

ghwdbbbas

Step-by-step explanation:

wdokdkktdkdkdkdkdkdkdkdkdkdkdkdkdkdkdkdkdkdkdkdkd

Tanya [424]3 years ago

6 0

Answer:

15000 i think it would be right

You might be interested in

Austen needs to buy a bathroom mirror that is 2 feet wide and 3 feet long. If the mirror

PtichkaEL [24]

<h2><u>Question :-</u></h2>

Austen needs to buy a bathroom mirror that is 2 feet wide and 3 feet long. If the mirror sells for $5.00 per square foot, what will the total cost of the mirror be?

<h2><u>Solution :-</u></h2>

<h3><u>Given Information :-</u></h3>

<u>Length of the mirror Austen needs to buy ➢</u> 3 ft
<u>Width of the mirror Austen needs to buy ➢</u> 2 ft
<u>Cost of mirror per square foot ➢</u> $5.00

Total cost of the mirror Austen needs to buy.

<h3><u>Formula Used :-</u></h3>

Area of Mirror = Length × Width
Total cost of mirror = Area of mirror × Cost of mirror per square foot

<h3><u>Calculation :-</u></h3>

<u>Area of mirror :-</u>

<em><u>Substituting the values given in the 1st formula, We get, </u></em>

⇒ Area of mirror = ( 3 × 2 ) ft²

⇒ Area of mirror = 6 ft²

<u>Now finding the total cost of mirror,</u>

<em><u>Substituting the values calculated above in the 2nd formula, We get </u></em>

⇒ Total Cost of mirror = $ ( 6 × 5.00 )

⇒ Total Cost of mirror = $30

<h2><u>Final Answer :-</u></h2>

Total cost of the mirror Austen needs to buy will be $30

7 0

2 years ago

Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f

pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁) = 0.999869

P(A/E₁) = 3% = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

$P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}$

$=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}$

$\frac{0.2999607}{0.00000393+0.2999607}$

$\frac{0.2999607}{0.29996463}$

= 0.999986898 ≈ 0.999987

6 0

3 years ago

A roll of wire has 51 inches of wire. If each bracelet requires 7.2 inches of wire, estimate the number of bracelets that can be

sergeinik [125]

Answer:

Step-by-step explanation:

51 ÷ 7.2 is about 7.08 continued but you can't make .08 of a braclet so it's just 7

8 0

3 years ago

What is 7.13×10 to the fifth power in standard form

horrorfan [7]

713000 is your answer

4 0

3 years ago

Please help me!

Alexxandr [17]

A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.

We can use the Pythagorean formula to find the other leg of the right triangle.

a²+b²=c²

Where a and b are the legs of the triangle and c is the hypotenuse.

According to the given problem,

one leg: a= 5m and hypotenuse: c=13√5 m.

So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,

5²+b²=(13√5)²

25 + b² = 13²*(√5)²

25 + b² = 169* 5

25+ b² = 845

25 + b² - 25 = 845 - 25

b² = 820

b =√ 820

b = √(4*205)

b = √4 *√205

b = 2√205

b= 2* 14.32

b = 28.64

So, b= 28.6 (Rounded to one decimal place)

Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).

5 0

3 years ago