1) Line should be parallel to y = 3x+6, so slope of this line should be =3.
y=mx +b
y=3x +b
Now we have to find b (y-intercept), using the point (-10, 2.5).
2.5 = 3*(-10)+b
b=2.5+30=32.5
y=3x + 32.5
2) The line should be perpendicular to y = -4x -2, so its slope is going to be negative reciprocal m= 1/4.
Now we have to find b (y-intercept), using the point (-16, -11).
y=(1/4)x +b
-11=(1/4)*(-16) + b
-11 = -4 +b
b = -7
y=(1/4)x - 7
0.133 because 5 mean you have to round up so it is 0.133
Answer:
- train: 40 kph
- plane: 140 kph
Step-by-step explanation:
Let t represent the speed of the train in km/h. Then 4t-20 is the speed of the plane. Travel times are the same, so we can use the formula ...
time = distance/speed
and equate the travel times.
110/t = 385/(4t-20)
Cross multiplying gives ...
110(4t -20) = 385t
440t -2200 = 385t . . . . . eliminate parentheses
55t -2200 = 0 . . . . . . . . . subtract 385t
t -40 = 0 . . . . . . . . . divide by 55
t = 40 . . . . . . . . . . . add 40; train's speed is 40 kph
4t -20 = 140 . . . . . . find plane's speed; 140 kph
The train's speed is 40 km/h; the plane's speed is 140 km/h.
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<em>Check</em>
Train's travel time = 110 km/(40 km/h) = 2.75 h.
Plane's travel time = 385 km/(140 km/h) = 2.75 h.
Answer:
4
Step-by-step explanation:
that was easy