Let the integers be x and x + 2, provided x is an even value.
The product is six more than 3 times their sum.
x(x + 2) = 6 + 3(x + (x + 2))
By expanding and simplifying, we get:
x² + 2x = 6 + 3(2x + 2)
x² + 2x = 6 + 6x + 6
x² + 2x = 12 + 6x
x² - 4x - 12 = 0
(x - 6)(x + 2) = 0
x = 6 or x = -2.
Thus, your integers are: 6 and 8 or -2 and 0
We need to first find a common denominator. This means that we need the 12 and the 3 to be the same number. We can change the 1/3 into 4/12 and see that 9/12 is larger than 4/12.
Answer:
(3,1) and radius is 6
h= 3 and k = 1
( x- 3)^2+( y-1)^2= (6)^2
(x- 3)^2+( y-1)^2= 36
Step-by-step explanation:
The formula for the equation of a circle is (x – h)^2+ (y – k)^2 = r^2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.
Answer:
Step-by-step explanation:
UV+VW=UW
19+4x-20=6x-35
4x-1=6x-35
34=2x
X=17
UW=19+4(17)-20
UW=67.
Answer:
3.5×10=35
3.5×22=77
10×3.5=35
1×22=22
(3.5)(10)=3.5 x 10
(3.5)(22)=3.5 x 22
(10)(3.5)=22 x 1.5909090909091
(1)(22)=3.5 x 6.2857142857143
Step-by-step explanation:
I didn't really understand the question.